Question

Simplify 9 to the 2nd over 9 to the 7th.

Answer 1

81/4782969
9/531441
3/177146
1/59049

Answer 2

Answer:

The simplified form of $\frac{9^2}{9^7}$ is $\frac{1}{9^5}$.

Step-by-step explanation:

Consider the provided information.

9 to the 2nd over 9 to the 7th

This can be written as:

$\frac{9^2}{9^7}$

Use the quotient rule of exponent:

$\frac{a^m}{a^n}=a^{m-n}$

By using the above rule.

$9^{2-7}$

$9^{-5}$

Now use the negative exponent rule: $a^{-n}=\frac{1}{a^n}$

By using the above rule:

$9^{-5}=\frac{1}{9^5}$

Hence, the simplified form of $\frac{9^2}{9^7}$ is $\frac{1}{9^5}$.