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Aleks [24]
4 years ago
11

What is the car is acceleration if it increases its speed from 5 meters per second to 20 m/s in three seconds

Physics
1 answer:
Marat540 [252]4 years ago
7 0
Initial Velocity, u=5m/s
Final Velocity, v=20m/s
Time, t=3s
Then we have acceleration, a=(v-u)÷t
a=(20-5)÷3=15÷3=5

The final answer is 5m/s²
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Answer: The lithosphere and the asthenosphere

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What would be the average fixed cost per unit at an activity level of 5,200 units? assume that this level of activity is within
Vitek1552 [10]

The average fixed cost per unit at an activity level of 5,200 units is $6.00.

<h3>What is the average fixed cost?</h3>

The average fixed cost (AFC) is fixed cost that does not change with the change in the number of goods and services produced by a company. To put it in a nutshell, average fixed cost (AFC) is the fixed cost per unit and is calculated by dividing the total fixed cost by output level.

Since no cost is fixed for a long time, average fixed cost is only for a short run. When units of production increase, the average fixed cost per unit decreases. Similarly, when the business produces less units, average cost increases per unit.

However, only one unit, mostly capital, is fixed. Examples of average fixed cost are the salaries of permanent employees, mortgage payment on machinery and plant, rent, more.

Average Fixed Cost Formula:

AFC = Total fixed cost/Output (Q)

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4 0
2 years ago
What's the difference between beam balance and spring balance?
seropon [69]
<span>A spring balance will give a different mass reading on the Moon from that on Earth. A beam balance however, will give the same reading.Explain why.

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<span>Beam Balance:

Beam balance measures mass.

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The S.I. unit of mass is kg


</span><span>
Spring Balance:

Spring balance measures weight not mass.

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That is why when we are in outer space, we become lighter-there is less gravity!</span>

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5 0
3 years ago
If, instead, the ball is revolved so that its speed is 3.7 m/s, what angle does the cord make with the vertical?
Delicious77 [7]

Complete Question:

A 0.50-kg ball that is tied to the end of a 1.5-m light cord is revolved in a horizontal plane, with the cord making a 30° angle with the vertical.

(a) Determine the ball’s speed. (b) If, instead, the ball is revolved so that its

speed is 3.7 m/s, what angle does the cord make with the vertical?

(Check attached image for the diagram.)

Answer:

(a) The ball’s speed, v = 2.06 m/s

(b) The angle the cord makes with the vertical is 50.40⁰

Explanation:

If the ball is revolved in a horizontal plane, it will form a circular trajectory,

the radius of the circle, R = Lsinθ

where;

L is length of the string

The force acting on the ball is given as;

F = mgtanθ

This above is also equal to centripetal force;

mgTan \theta = \frac{mv^2}{R} \\\\Recall, R = Lsin \theta\\\\mgTan \theta = \frac{mv^2}{Lsin \theta}\\\\v^2 = glTan \theta sin \theta\\\\v = \sqrt{glTan \theta sin \theta} \\\\v = \sqrt{(9.8)(1.5)(Tan30)(sin30)} \\\\v = 2.06 \ m/s

(b) when the speed is 3.7 m/s

v = \sqrt{glTan \theta sin \theta} \ \ \ ;square \ both \ sides\\\\v^2 = glTan \theta sin \theta\\\\v^2 = gl(\frac{sin \theta}{cos \theta})   sin \theta\\\\v^2 = \frac{gl*sin^2 \theta}{cos \theta} \\\\v^2 =  \frac{gl*(1- cos^2 \theta)}{cos \theta}\\\\gl*(1- cos^2 \theta) = v^2cos \theta\\\\(9.8*1.5)(1- cos^2 \theta) = (3.7^2)cos \theta\\\\14.7 - 14.7cos^2 \theta = 13.69cos \theta\\\\14.7cos^2 \theta  + 13.69cos \theta - 14.7 = 0 \ \ \ ; this \ is \ quadratic \ equation\\\\

Cos\theta = \frac{13.69\sqrt{13.69^2 -(-4*14.7*14.7)} }{14.7} \\\\Cos \theta = 0.6374\\\\\theta = Cos^{-1}(0.6374)\\\\\theta = 50.40 ^o

Therefore, the angle the cord makes with the vertical is 50.40⁰

7 0
3 years ago
Suppose a treadmill has an average acceleration of .0050 m/s2. How much does it's speed changer after 4.8 minutes?
avanturin [10]
This one is nice and straight forward :)

simply calculate how many seconds are in 4.8 minutes like this:
4.8min x 60s = 288s

Then to find the ∆v (∆v = symbol for change in velocity) multiply the acceleration 0.0050m/s^2 by 288s
∆v = 1.44m/s



0.0050m/sx^{2}




3 0
4 years ago
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