Since they are both examples of moving waves, they both transmit energy.
E, 63% of the value. I forget the rationale behind it but I learnt that in engineering. 90% confident for that answer.
Answer:
the correct answer is see.
Explanation:
it is wat it isssssssssss
I think your question should be:
An industrial laser is used to burn a hole through a piece of metal. The average intensity of the light is

What is the rms value of (a) the electric field and
(b) the magnetic field in the electromagnetic wave emitted by the laser
Answer:
a) 
b) 
Explanation:
To find the RMS value of the electric field, let's use the formula:

Where
;
;

Therefore
![E_r_m_s = sqrt*{(1.239*10^9W/m^2) / [(3.00*10^8m/s)*(8.85*10^-^1^2C^2/N.m^2)]}](https://tex.z-dn.net/?f=%20E_r_m_s%20%3D%20sqrt%2A%7B%281.239%2A10%5E9W%2Fm%5E2%29%20%2F%20%5B%283.00%2A10%5E8m%2Fs%29%2A%288.85%2A10%5E-%5E1%5E2C%5E2%2FN.m%5E2%29%5D%7D%20)

b) to find the magnetic field in the electromagnetic wave emitted by the laser we use:
;
;
