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horrorfan [7]
3 years ago
8

Will each of the following actions increase the distance between the diffraction spots? a) Increase the distance between the scr

een and the grating. (Yes or No) (1pt.) b) Rotate the grating by 90 degrees. (Yes or No) (1pt.) c) Use a different light source that has a longer wavelength. (Yes or No) (1pt.) d) Double the screen size. (Yes or No) (1pt.) e) Use a different grating that has a higher line density. (Yes or No) (1pt.)
Physics
1 answer:
diamong [38]3 years ago
5 0

Answer:

A) no

B) no

C) yes

D) no

E) yes

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When do we land on Mars ?
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Answer:

I think like 2024 or 25

Explanation:

Elon musk will probably go

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Suppose that sunlight is incident upon both a pair of reading glasses and a pair of sunglasses. Which pair would you expect to b
Ainat [17]

Answer: the pair of sunglasses

Explanation:

A good pair of sunglasses are composed of abosorbent lenses that filter the sunlight that affects the eyes retina, especially ultraviolet (UV). So, these sunglasses are used to reduce the amount of light or radiant energy transmitted.

On the other hand, normal reading glasses (in which the lens glass has not been treated to filter ultraviolet sunlight) will let UV rays pass through.

Therefore, if both glasses are exposed to sunlight, the sunglasses are expected to be warmer by absorbing that radiant energy and preventing it from reaching the eyes.

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3 years ago
What circumstance would allow an officer to search a home even if they didn’t have a warrant?
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Answer:

A

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The officer would have had permission regardless of anything else, kind of like letting someone into your house.

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3 years ago
Describe how a metamorphic rock might become a sedimentary rock over time.
andriy [413]
<span>Metamorphic rock undergoes weathering, erosion; the particles are deposited and undergo lithification.</span>
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3 years ago
The drawing shows an adiabatically isolated cylinder that is divided initially into two identical parts by an adiabatic partitio
Sveta_85 [38]

Answer:

temperature on left side is 1.48 times the temperature on right

Explanation:

GIVEN DATA:

\gamma = 5/3

T1 = 525 K

T2 = 275 K

We know that

P_1 = \frac{nRT_1}{v}

P_2 = \frac{nrT_2}{v}

n and v remain same at both side. so we have

\frac{P_1}{P_2} = \frac{T_1}{T_2} = \frac{525}{275} = \frac{21}{11}

P_1 = \frac{21}{11} P_2 ..............1

let final pressure is P and temp  T_1 {f} and T_2 {f}

P_1^{1-\gamma} T_1^{\gamma} = P^{1 - \gamma}T_1 {f}^{\gamma}

P_1^{-2/3} T_1^{5/3} = P^{-2/3} T_1 {f}^{5/3} ..................2

similarly

P_2^{-2/3} T_2^{5/3} = P^{-2/3} T_2 {f}^{5/3} .............3

divide 2 equation by 3rd equation

\frac{21}{11}^{-2/3} \frac{21}{11}^{5/3} = [\frac{T_1 {f}}{T_2 {f}}]^{5/3}

T_1 {f} = 1.48 T_2 {f}

thus, temperature on left side is 1.48 times the temperature on right

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3 years ago
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