Explanation:
Electrons will gain energy as they are "pushed" from different points in the circuit. This energy is then lost when the electrons flow through circuit components such as a light bulb.
Explanation:
It is given that,
The angular acceleration of the basketball, 
Time taken, t = 3 seconds
We need to find the ball’s final angular velocity if the ball starts from rest. It can be calculated using definition of angular acceleration i.e.





So, the ball's final angular velocity is 30 rad/s. Hence, this is the required solution.
Answer:
Speed of block after the bullet emerges = 1.5 m/s
Explanation:
Here momentum is conserved.
Initial momentum = Final momentum.
Mass of bullet = 10 g = 0.01 kg
Initial Velocity of bullet = 300 m/s
Mass of block = 1 kg
Initial Velocity of block = 0 m/s
Final Velocity of bullet = 50% of initial velocity. = 150 m/s
We need to find final velocity of block. Let it be v
We have
Initial momentum = 0.01 x 300 + 1 x 0 = 3 kg m/s
Final momentum = 0.01 x 150 + 1 x v = 1.5 + v
Equating
3 = 1.5 + v
v = 1.5 m/s
Speed of block after the bullet emerges = 1.5 m/s
Refer to the diagram shown below.
The component of the applied force perpendicular to the door is
F * sin(60°) = 0.866F N
Because the moment arm is 0.40 m, the torque is
(0.866F N)*(0.4 m) = 0.3464F N-m
This torque is equal to 1.4 N-m, therefore
0.3464F = 1.4
F = 4.04 N
Answer: 4.04 N