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algol [13]
3 years ago
5

The wavelengths of light emitted by a firefly span the visible spectrum but have maximum intensity near 550 nm. A typical flash

lasts for 100 ms and has a power of 1.2 mW. If we assume that all of the light is emitted at the peak-intensity wavelength of 550 nm, how many photons are emitted in one flash?
Physics
1 answer:
Reil [10]3 years ago
3 0

Answer:

3.3\cdot 10^{15}

Explanation:

First of all, let's calculate the energy of a single photon of wavelength

\lambda=550 nm=5.5\cdot 10^{-7}m

which is given by

E_1 = \frac{hc}{\lambda}=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{5.5\cdot 10^{-7} m}=3.6\cdot 10^{-19} J

The power of the flash is

P=1.2 mW=0.0012 W

and the time it lasts is

t=100 ms=0.1 s

so the total energy delivered in one flash is

E=Pt=(0.0012 W)(0.1 s)=1.2\cdot 10^{-3}J

This energy contains exactly N photons each of energy E_1, so the number of photons emitted in one flash is

N=\frac{E}{E_1}=\frac{1.2\cdot 10^{-3} W}{3.6\cdot 10^{-19}J}=3.3\cdot 10^{15}

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A straight wire segment 5 m long makes an angle of 30° with a uniform magnetic field of 0.37 T. Find the magnitude of the force
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Answer:

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Explanation:

Given that,

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We need to find the magnitude of the force on the wire. The magnetic force in the wire is given by :

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Answer:

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r=1.91\times 10^{-14}\ m

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