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mote1985 [20]
3 years ago
5

As we move through the visible spectrum, red to violet (right to left in the image), the wavelength __________ and the frequency

____________.
A) increases; decreases

B) increases; increases

C) decreases; increases

D) decreases; decreases
Physics
2 answers:
Igoryamba3 years ago
7 0
As we move through the visible spectrum, red to violet (right to left in the image), the wavelength decreases and the frequency increases. The correct option among all the options that are given in the question is the third option or option "C". I hope this answer helps you and you will understand the solution also. 
Lynna [10]3 years ago
6 0
<h3><u>Answer;</u></h3>

C) decreases; increases

<h3><u>Explanation;</u></h3>
  • As we move through the visible spectrum, red to violet (right to left in the image), the wavelength <u><em>decreases</em></u> and the frequency <em><u>increases</u></em>.
  • <em><u>Electromagnetic spectrum comprises of electromagnetic waves arranged in the order of increasing or decreasing frequency and wavelength.</u></em>
  • These electromagnetic waves includes; <em><u>radio waves, microwaves, infrared, visible light, ultraviolet, x-rays and gamma rays. </u></em>
  • In electromagnetic spectrum as you move from left to right, <em><u>that is from the radio waves towards the gamma rays, the wavelength decreases as the frequency increases; while from gamma rays towards the radio waves the wavelength increases while the frequency decreases.</u></em>
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You are on the roof of the physics building, 46.0 above the ground . Your physics professor, who is 1.80 tall, is walking alongs
nekit [7.7K]

There is one mistake in the question as unit of height of building is not given.So I assume it as meter.The complete question is here

You are on the roof of the physics building, 46.0 m above the ground. Your physics professor, who is 1.80 m tall, is walking alongside the building at a constant speed of 1.20 m/s. If you wish to drop an egg on your professor’s head, where should the professor be when you release the egg? Assume that the egg is in free fall.  

Answer:

d=3.67 m

Explanation:

Height of building=46.0 m

First we need to find time taken by egg to reach 1.80 m above the surface

So to find time use below equation

S=vt+\frac{1}{2} gt^{2}\\ (46.0-1.80)m=(om/s)t+\frac{1}{2}(9.8m/s^{2} )t^{2}\\t=\sqrt{\frac{(46.0-1.80)m}{4.9} }\\ t=3.06s

As velocity 1.20m/s is given and we have find time.So we can easily find the distance

So

distance=velocity*time\\d=v*t\\d=(1.20m/s)*(3.06s)\\d=3.67m

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