Answer:
7557.875 J
Explanation:
Assumimg we need to find work done by the bullet on the gas
The work is found by integrating force over distance
W= 
For the force in this problem we have
= ![[14000x+10000x^2-21000x^3]_{0}^{0.65}](https://tex.z-dn.net/?f=%5B14000x%2B10000x%5E2-21000x%5E3%5D_%7B0%7D%5E%7B0.65%7D)
=7557.875 J
Gravitational potential energy is associated with the shape or position of an object.
1.)When an object is placed at height h above ground, gravitational potential energy associated with it is given by,
P.E = mgh
2.)In projectile motion during upward motion, kinetic energy of object is converted into potential energy.
1. no, they have a good method already but new tech could help in terms of laboring.
Dark matter pulls the moon around earth in a circular pattern
Answer:
Explanation:
Let the frictional upward force be F = 550 N
Net force on it = mg - F
82 X 9.8 - 550
= 803.6 - 550
253.6 N
Downward acceleration = 253.6 / 82
= 3.0927 m / s²
final velocity after slipping 5.2 m , v then
v² = 2 x a s
= 2 x 3.0927 x 5.2
v = 5.67 m /s
It stops in .45 m distance
v² = u² - 2as
0 = 5.67² - 2 a x .45
a = - 35.72 m / s²
