The standard form of hyperbola is:
(x-h)²/a²-(y-k)²/b²=1
center:(4,5)
Length of the horizontal transverse axis: 8-5=3=2a
thus
a=3/2
a²=9/4
b=2
b²=4
Hence the equation will be:
(x-4)²/(9/4)-(y-5)²/4=1
simplifying this we get:
[4(x-4)²]/9-(y-5)²/4=1
I Dun know I hope u know the answer
Put your problem in this https://www.cymath.com/ its awesome at solving x
In case you're not already aware, the expression
is called the "difference quotient" and represents the average rate of change of a function
over an interval
.
For the function
, by substituting
we get

Then the difference quotient is


where the last equality holds as long as
.
Answer:
Let coordinates of vertex D be (x,y)
In parallelogram diagonals are bisect each other.
∴ Mid-point of AC= Mid-point of BD
⇒ (
2
3+(−6)
,
2
−4+2
)=(
2
−1+x
,
2
−3+y
)
⇒ (
2
−3
,
2
−2
)=(
2
−1+x
,
2
−3+y
)
⇒ (
2
−3
,−1)=(
2
−1+x
,
2
−3+y
)
Now,
⇒
2
−3
=
2
−1+x
⇒ −6=−2+2x
⇒ −4=2x
∴ x=−2
⇒ −1=
2
−3+y
⇒ −2=−3+y
⇒ 1=y
∴ y=1
∴ Coordinates of vertex D is (−2,1)