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Wewaii [24]
3 years ago
15

A polygon has an angle sum of 180 and each angle measures 60. What is the polygon?

Mathematics
1 answer:
Vladimir79 [104]3 years ago
6 0
Idk what the answer  is to your question

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The hyperbola with center at (4, 5), with vertices at (0, 5) and (8, 5), with b = 2.
galina1969 [7]
The standard form of hyperbola is:
(x-h)²/a²-(y-k)²/b²=1
center:(4,5)
Length of the horizontal transverse axis: 8-5=3=2a
thus
a=3/2
a²=9/4
b=2
b²=4

Hence the equation will be:
(x-4)²/(9/4)-(y-5)²/4=1
simplifying this we get:
[4(x-4)²]/9-(y-5)²/4=1
8 0
3 years ago
Can someone help me on problem one and two?
nevsk [136]
I Dun know I hope u know the answer
3 0
2 years ago
Solve for x.<br> −32 &amp;&gt; −5 9x
Kobotan [32]
Put your problem in this  https://www.cymath.com/  its awesome at solving x 

7 0
3 years ago
If f(x)=x^2+3x+4 which of the number choices represents (f(x+h)-f(x))/h?
Helen [10]

In case you're not already aware, the expression \frac{f(x+h)-f(x)}h is called the "difference quotient" and represents the average rate of change of a function f over an interval [x,x+h].

For the function f(x)=x^2+3x+4, by substituting x+h we get

f(x+h)=(x+h)^2+3(x+h)+4=(x^2+2xh+h^2)+(3x+3h)+4=x^2+3x+4+(2x+3)h+h^2

Then the difference quotient is

\dfrac{f(x+h)-f(x)}h=\dfrac{(x^2+3x+4+(2x+3)h+h^2)-(x^2+3x+4)}h

=\dfrac{(2x+3)h+h^2}h=2x+3+h

where the last equality holds as long as h\neq0.

5 0
3 years ago
WILL GIVE BRAINLIEST
EastWind [94]

Answer:

Let coordinates of vertex D be (x,y)

In parallelogram diagonals are bisect each other.

∴ Mid-point of AC= Mid-point of BD

⇒ (

2

3+(−6)

,

2

−4+2

)=(

2

−1+x

,

2

−3+y

)

⇒ (

2

−3

,

2

−2

)=(

2

−1+x

,

2

−3+y

)

⇒ (

2

−3

,−1)=(

2

−1+x

,

2

−3+y

)

Now,

⇒

2

−3

=

2

−1+x

⇒ −6=−2+2x

⇒ −4=2x

∴ x=−2

⇒ −1=

2

−3+y

⇒ −2=−3+y

⇒ 1=y

∴ y=1

∴ Coordinates of vertex D is (−2,1)

7 0
3 years ago
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