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3 years ago

The electrons of an atom store nuclear energy.

Physics

2 answers:

Makovka662 [10]3 years ago

5 0

Answer:

False

Explanation:

This statement is False.

The atom is made up of nucleus in which there are neutrons and protons and electrons which are revolving around the atom's nucleus.

nuclear energy is basically energy the source of which is nucleus of the atom. there are two methods by which nuclear energy is produces.

1) Nuclear fission

2) nuclear fusion

In nuclear fission, the neutron is bombarded on the nucleus of an atom of an element. It splits and produces a daughter nucleus, neutrons and huge amount of energy

In nuclear fusion, two nuclei of the atoms fuse and produce huge amount of energy.

In both of above mentioned cases, there is neither any role of electrons to produce energy nor in storing nuclear energy.

So, the given statement is wrong

Key words: Nucleus, Nuclear energy, electron, Nuclear fission, Nuclear fusion, neutrons, atom

Sladkaya [172]3 years ago

4 0

False. The nuclear energy is found within the nucleus. Electrons are located outside the nucleus.

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A circular coil of radius r = 5 cm and resistance R = 0.2 is placed in a uniform magnetic field perpendicular to the plane of th

Yuri [45]

Answer:

the question is incomplete, the complete question is

"A circular coil of radius r = 5 cm and resistance R = 0.2 ? is placed in a uniform magnetic field perpendicular to the plane of the coil. The magnitude of the field changes with time according to B = 0.5 e^-t T. What is the magnitude of the current induced in the coil at the time t = 2 s?"

2.6mA

Explanation:

we need to determine the emf induced in the coil and y applying ohm's law we determine the current induced.

using the formula be low,

$E=-\frac{d}{dt}(BACOS\alpha )\\$

where B is the magnitude of the field and A is the area of the circular coil.

First, let determine the area using $\pi r^{2} \\$ where r is the radius of 5cm or 0.05m

$A=\pi *(0.05)^{2}\\ A=0.00785m^{2}\\$

since we no that the angle is at $0^{0}$

we determine the magnitude of the magnetic filed

$B=0.5e^{-t} \\t=2s$

$E=-(0.5e^{-2} * 0.00785)$

$E=-0.000532v\\$

the Magnitude of the voltage is 0.000532V

Next we determine the current using ohm's law

$V=IR\\R=0.2\\I=\frac{0.000532}{0.2} \\I=0.0026A$

$I=2.6mA$

6 0

3 years ago

You are sitting on a deck of your house surrounded by oak trees. You hear the sound of an acorn hitting the deck. You wonder if

Black_prince [1.1K]

Answer: 96N

Explanation:

To calculate the velocity of the impact On the persons head, we have

h = gt²/2

14 = 9.81t²/2

t² = 28/9.8

t² = 2.86

t = 1.69s

V = u + at

V = 0 + 9.81*1.69

V = 16.58m/s

a(average) = (v1² + v2²) /2Δy

a(average) = 16.58² + 0)/2 * 0.005

a(average) = 274.8964/0.01

a(average) = 27489.64m/s²

Using newton's second law of motion,

F(average) = m * a(average)

F(average) = 0.0035 * 27489.64

F(average) = 96.21N

Therefore the force needed by the acorn to do much damage starts from 96N

8 0

3 years ago

A sealed beaker of what you are told is aqueous nickel sulfide was given to you by the local chemist and you put it on the windo

Masteriza [31]

Answer: D. It is a SUSPENSION

Explanation:

SUSPENSION

This is a combination of two or more single substances. The properties of the components involved are not however changed or lost as is the case with compounds.

For this reason this mixture can be separated due to sedimentation or filtering.

After a few days, this occurs in the aqueous nickel sulfide because the solid nickel sulfide is separating from the water.

7 0

3 years ago

Why does the weather change during an eclipse? help me

Otrada [13]

Answer:

here`s your answer

Winds often slow down during an eclipse as the atmosphere temporarily settles. Heating causes the atmosphere to mix and bubble, just like a pot of water on the stove. As it warms, the water level in the pot rises because warm objects, including water, expand. In the case of the atmosphere, it also expands when heated.

Explanation:

5 0

3 years ago

How much current is in a circuit that includes a 9.0 volt battery and a bulb woth a resistance of 4.0 ohms

Vitek1552 [10]

According to Ohm's law for a portion of the circuit we have:

U=RI=>I=U/R=9/4=2.25 A

7 0

3 years ago

Read 2 more answers