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3 years ago

How much current is in a circuit that includes a 9.0 volt battery and a bulb woth a resistance of 4.0 ohms

Physics

2 answers:

Elza [17]3 years ago

8 0

Answer:

Current in the circuit, I = 2.25 A

Explanation:

Given that,

Voltage of the battery, V = 9 V

Resistance of the bulb, R = 4 ohms

We need to find the current in the circuit. It can be calculated using Ohm's law. Ohm's law gives the relationship between the current, resistance and the voltage as :

$V=IR$

$I=\dfrac{V}{R}$

$I=\dfrac{9\ V}{4\ \Omega}$

I = 2.25 A

So, the current flowing in the circuit is 2.25 amperes. Hence, this is the required solution.

Vitek1552 [10]3 years ago

7 0

According to Ohm's law for a portion of the circuit we have:

U=RI=>I=U/R=9/4=2.25 A

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Explanation:

Given that,

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3 years ago

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2 years ago

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NARA [144]

Answer:

Explanation:

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k = 4.5 x 10¹ = 45 N/m

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3 years ago

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3 years ago

You are designing a simple elevator system for an old warehouse that is being converted to loft apartments. A 22,500-N elevator

ICE Princess25 [194]

Answer:

A) mass = 3121.58 kg

B) tension = 25940.37 N

C) tension = 25940.37 N (tension on both sides will be the same)

Explanation:

Weight of elevator = 22500 N

Distance = 6.75 m

Time = 3 sec

Since it started from rest, initial speed is zero.

Using Newton's equation of motion we have,

S = ut + 0.5at^2

S = distance covered = 6.75 m

t = time = 3 s

a = acceleration upwards

u = initial velocity = 0

Substituting values, we have,

6.75 = 0(3) + (0.5 x a x 3^2)

6.75 = 4.5a

a = 6.75/4.5 = 1.5 m/s^2 (acceleration of the elevator upwards)

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Where g = acceleration due to gravity 9.81 m/s

Mass = 22500/9.81 = 2293.58 kg

From the image below we solve from

T - 22500 = ma

T - 22500 = 2293.58 x 1.5

T - 22500 = 3440.37

T = 3440.37 + 22500 = 25940.37 N (this is the tension on the rope)

On the other side,

mg - T = ma

9.81m - 25940.37 = 1.5m

(9.81 - 1.5)m = 25940.37

8.31m = 25940.37

m = 3121.58 kg (mass of counter weight)

See image below

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3 years ago