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3 years ago

1)

Physics

1 answer:

Ket [755]3 years ago

3 0

Answer:

1) D

2) A

Explanation:

1) Each group has the same number of valence electrons, which are the outer electrons.

2) Ionic bonds are between a metal and non - metal, the metal being sodium and the non - metal being chlorine.

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Which of the following changes will always increase the efficiency of a thermodynamic engine? Choose all correct statements.

Ilya [14]

Answer:B,C,D

Explanation:

Thermodynamic efficiency is given by

$\eta =1-\frac{T_C}{T-H}$

$\eta$ efficiency can be increased by Keeping $_c$ constant and increasing $T_H$

Keeping $T_H$ constant and decreasing $T_c$

by increasing $\Delta T=T_H-T_c$

by decreasing $\frac{T_C}{T_H}$ ratio

5 0

3 years ago

Read 2 more answers

A car is traveling at a speed of 45 km/h into town. It takes the car 2 hours to get there. How far has the car traveled?

hjlf

Answer:

90 km

Explanation:

45 km per hr

2 hrs

45 x 2 = 90

90 km/2 hrs

Hope this helps!

7 0

3 years ago

Read 2 more answers

Ahmad is riding his bicycle. He finds that he can accelerate from rest at 0.44 m/s^2 for 5 s to reach a speed of 2.2 m/s. The to

snow_lady [41]

Answer:

1) The force Christian can exert on his bicycle before picking up the the cargo is 529.74 N

2) The force Christian can exert on his bicycle after picking up the the cargo is 647.46 N

Therefore, Christian has to exert more force on his bike after picking up the cargo

Explanation:

The given parameters are;

The mass of Christian and his bicycle = 54 kg

The mass of the cargo = 12 kg

1) The force Christian can exert on his bicycle before picking up the the cargo = Mass of Christian and his bicycle × Acceleration due to gravity

∴ The force Christian can exert on his bicycle before picking up the the cargo = 54 kg × 9.81 m/s² = 529.74 N

2) The force Christian can exert on his bicycle after picking up the the cargo = (54 + 12) kg × 9.81 m/s² = 647.46 N

Therefore, Christian has to exert more force on his bike after picking up the cargo.

7 0

3 years ago

Air is cooled in a process with constant pressure of 150 kPa. Before the process begins, air has a specific volume of 0.062 m^3/

Mama L [17]

Answer:

The pressure is constant, and it is P = 150kpa.

the specific volumes are:

initial = 0.062 m^3/kg

final = 0.027 m^3/kg.

Then, the specific work can be written as:

$W = \int\limits^{vf}_{vi} {Pdv} \, = P(vf - vi) = 150kPa*(0.0027 - 0.062)m^3/kg = -5.25 kPa*m^3/kg.$

The fact that the work is negative, means that we need to apply work to the air in order to compress it.

Now, to write it in more common units we have that:

1 kPa*m^3 = 1000J.

-5.25 kPa*m^3/kg = -5250 J/kg.

7 0

3 years ago

Two loudspeakers are placed next to each other and driven by the same source at 500 Hz. A listener is positioned in front of the

stellarik [79]

To solve this problem we will apply the concepts related to wavelength as the rate of change of the speed of the wave over the frequency. Mathematically this is

$\lambda = \frac{v}{f}$

Here,

v = Wave velocity

f = Frequency,

Replacing with our values we have that,

$\lambda = \frac{340}{500}$

\lambda = 0.68m

The distance to move one speaker is half this

$\lambda/2 = 0.34m$

Therefore the minimum distance will be 0.34m

7 0

3 years ago