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Tanya [424]
3 years ago
5

Turning the barrel of a 50-mm-focal-length lens on a manual-focus camera moves the lens closer to or farther from the sensor to

focus on objects at different distances. The lens has a stated range of focus from 0.70 m infinity.
How far does the lens move between these two extremes?
Physics
1 answer:
Yuliya22 [10]3 years ago
4 0

Answer:

Explanation:

To focus object at .7m , the image distance can be measured as follows

object distance u = .7m

focal length f = .05 m

image distance v = ?

from lens formula

\frac{1}{v} -\frac{1}{u} = \frac{1}{f}

\frac{1}{v} +\frac{1}{.7} = \frac{1}{.05}

\frac{1}{v} =\frac{1}{.05} -\frac{1}{.7}

v = .054 m

= 54 mm

when the object is at infinity , image is formed at focus ie at distance of

50 mm .

So lens position from sensor  where image is formed , varies from 54 mm to 50 mm .

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<h3>Concave or diverging lens is needed correct the vision of a nearsighted person  whose far point is 30.0 cm</h3>

<em><u>Solution:</u></em>

Nearsighted person will not be able to see the distant objects clearly

Now, we want the near sighted person to see the distant objects clearly

<em><u>The lens equation is given as:</u></em>

P = \frac{1}{d_o} + \frac{1}{d_i}

For distant vision, d_0 = \infty

d_i = image\ distance\\\\d_0 = lens\ to\ retina\ distance

The image of 30 cm from eye will be 28.5 cm to left of spectacle lens

Therefore,

d_i = -28.5\ cm = 0.285\ meter

From lens equation,

P = \frac{1}{ \infty } + \frac{1}{-0.285\ meter}\\\\P = 0 - 3.51 \\\\P = -3.51\ diopter

The negative power -3.51 D denotes that a concave or diverging lens is needed

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3 years ago
The same force that causes a pop fly to smack into your baseball mitt keeps the Moon in its orbit around Earth. Agree Disagree E
Mademuasel [1]

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Explanation:

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7 0
2 years ago
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