Help me pls math and will make brainless<br> Answer 7. Pls !!!

Statements apply to the expression 8^3 ?check all that apply

hram777 [196]

Answer: So, 8%3 = 2

Step-by-step explanation:

6 0

3 years ago

There are 90 girls and 60 boys in the sixth grade at a middle school. Of these students, 7 girls and 2 boys write left-handed. W

Radda [10]

Answer:

6%

Step-by-step explanation:

90 + 60 = 150
7 + 2 = 9
Set up a proportion: $\frac{9}{150} = \frac{x}{100}$
Cross multiply, then divide: 9 × 100 = 900, 900 ÷ 150 = 6
So, 6% of students in 6th grade were left-handed

I hope this helps!

6 0

3 years ago

Read 2 more answers

Somebody who knows how to do this?? plz answer all the questions correctly thanks!

Ksju [112]

Answer:

a) 5/21

b) 4/21

c) 4/21

d) 8/21

Step-by-step explanation:

total number of coins: 21

a) number if dollars: 5

therefore fraction is 5/21

b) number of quarters: 4

therefore fraction is 4/21

c) number of dimes: 4

therefore fraction is 4/21

d) number of nickels: 8

therefore fraction is 8/21

4 0

3 years ago

If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree) A) 32.5° B) 39.2° C) 50.5° D) 57.5°

Ilia_Sergeevich [38]

Answer:

D) 57.5°

Step-by-step explanation:

As the question is not complete. So, let's suppose it is a right angle triangle then, we can apply Pythagoras theorem to calculate the hypotenuse or the third side.

Pythagoras Theorem = $c^{2}$ = $a^{2} + b^{2}$

a = 7 and b = 11

$a^{2}$ = 49

$b^{2}$ = 121

Plugging in the values, we will get:

$c^{2}$ = 49 + 121

$c^{2}$ = 170

c = $\sqrt{170}$

To calculate the unknown angle B, we can use law of sine.

Law of sine = $\frac{a}{sinA}$ = $\frac{b}{sinB}$ = $\frac{c}{sinC}$

So,

$\frac{c}{sinC}$ = $\frac{b}{sinB}$

$\frac{\sqrt{170} }{sin90}$ = $\frac{11}{sinB}$

Sin90 = 1

sinB = $\frac{11}{\sqrt{170} }$

B = $sin^{-1}$ ( $\frac{11}{\sqrt{170} }$ )

B = 57.5°

8 0

3 years ago

Just Need A Few Questions Answered To Finish My Quiz, Any Help Would Be Much Appreciated.

kvv77 [185]

Given the triangle

PQR

with points

P(8,0)

Q(6,2)

R(-2,-4)

And the triangle

P'Q'R'

with points

P'(4,0)

Q'(3,1)

R'(-1,-2)

Part A. Scale factor

Using the vertex

P( 8, 0)

P'(4,0)

the dilatation factor is given by

$\frac{4}{8}=\frac{1}{2}$

The triangle has a dilatation factor of 1/2

Part B:

P''Q''R'' after using P'Q'R' reflected about the y axis

to make a reflection over the y axis

coordinates (x,y) turn into coordinates (-x,y)

as follows

$P^{\prime}(4,0)\rightarrow P^{\prime\prime}(-4,0)$ $Q^{\prime}(3,1)\rightarrow Q^{\prime\prime}(-3,1)$ $R^{\prime}(-1,-2)\rightarrow R^{\prime\prime}(1,-2)$

Then triangle P''Q''R'' has coordinates

P''(-4,0)

Q''(-3,1)

R''(1,-2)

Part C:

PQR is congruent to P''Q''R''?

Congruent triangles are triangles that have the same size and shape. This means that the corresponding sides are equal and the corresponding angles are equal.

Then the triangles are not congruent

8 0

11 months ago

Help me pls math and will make brainless Answer 7. Pls !!!