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vlabodo [156]
3 years ago
9

An angle that measures between 90 and 180 is called?

Mathematics
2 answers:
Svetach [21]3 years ago
6 0
Obtuse would be correct :)

Law Incorporation [45]3 years ago
5 0
It's called an obtuse angle.
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Daniel worked for 2 1/3 hours and earned $18.20. How much would he make if he worked for 5 1/4 hours? Enter your answer in the b
Aleks04 [339]
2 1/3hrs→ $18.20
1 hr→ $7.80
5 1/4hrs→ $7.80x5 1/4= $40.95
5 0
3 years ago
Read 2 more answers
20 points and brainlyest to who answers this first in a well format!
djverab [1.8K]

Answer:

in the forth line of the equation it should be this

-6x+10=4x+20

-6x-4x=20-10

-10/-10x=10/-10

x=-1

5 0
3 years ago
Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)
babunello [35]

\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k

We want to find f(x,y,z) such that \nabla f=\vec F. This means

\dfrac{\partial f}{\partial x}=x^2+y

\dfrac{\partial f}{\partial y}=y^2+x

\dfrac{\partial f}{\partial z}=ze^z

Integrating both sides of the latter equation with respect to z tells us

f(x,y,z)=e^z(z-1)+g(x,y)

and differentiating with respect to x gives

x^2+y=\dfrac{\partial g}{\partial x}

Integrating both sides with respect to x gives

g(x,y)=\dfrac{x^3}3+xy+h(y)

Then

f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+h(y)

and differentiating both sides with respect to y gives

y^2+x=x+\dfrac{\mathrm dh}{\mathrm dy}\implies\dfrac{\mathrm dh}{\mathrm dy}=y^2\implies h(y)=\dfrac{y^3}3+C

So the scalar potential function is

\boxed{f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+\dfrac{y^3}3+C}

By the fundamental theorem of calculus, the work done by \vec F along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it L) in part (a) is

\displaystyle\int_L\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(4,0,0)=\boxed{1+3e^4}

and \vec F does the same amount of work over both of the other paths.

In part (b), I don't know what is meant by "df/dt for F"...

In part (c), you're asked to find the work over the 2 parts (call them L_1 and L_2) of the given path. Using the fundamental theorem makes this trivial:

\displaystyle\int_{L_1}\vec F\cdot\mathrm d\vec r=f(0,0,0)-f(4,0,0)=-\frac{64}3

\displaystyle\int_{L_2}\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(0,0,0)=\frac{67}3+3e^4

8 0
3 years ago
Match the independent variable, dependent variable and constant for the following statement.
den301095 [7]
Independent: cell phone plan
dependent: monthly cost
constant: per month/per minute (money)
5 0
3 years ago
At lunchtime 5/6 of students buy juice. Of those students 3/4 buy orange juice. What fraction of the students buy orange juice?
IrinaK [193]

5/6 × 3/4

=5/2 × 1/4

=5/8

Answer

5/8 students buy orange juice

7 0
3 years ago
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