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alina1380 [7]
4 years ago
14

How to tell if a number approaching inifnity is equal to -1?

Mathematics
1 answer:
Bumek [7]4 years ago
3 0
You can just make limit as x--->infinity
for this function
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Please show work: This is for my daughter in 7th. Grade; Needed some insight 15 Points, and Brainliest to whom show work with co
levacccp [35]

Answer:

1a. 42 liters

1b. 345 miles

2a. 10 h 20 min 41.4 sec

2b. 361.6 km

5a. $8

5b. 444.5 km

5c. 46 h 13 min 20.9 sec

5d. $160

Step-by-step explanation:

Each of these problems expresses a proportion and asks you to find a missing value. You are given, for example, <em>value 1</em> and <em>related value 1.</em> You are asked to find <em>value 2</em> that corresponds to <em>related value 2</em>.

<em>Solving the Proportion</em>

Expressed as a proportion, this looks like ...

... (<em>value 1</em>)/(<em>related value 1</em>) = (<em>value 2</em>)/(<em>related value 2</em>)

If you multiply both sides of this equation by <em>related value 2</em>, you can find <em>value 2</em>.

... (<em>related value 2</em>)/(<em>related value 1</em>)×(<em>value 1</em>) = <em>value 2</em>

<em>Another way to think about it</em>

I like to think of the <em>related values</em> as making a fraction. If the <em>related value 2</em> is larger than <em>related value 1</em>, the fraction is greater than 1 and the <em>value 2</em> will be larger than <em>value 1</em>. (This realization can serve as a check on your answer.)

1a. <em>related value 2</em> = 168 km. This is the value for which you want to find <em>value 2</em>, the number of liters of gasoline. <em>related value 1</em> has the same units as <em>related value 2</em> (km), and <em>value 1</em> has the same units as <em>value 2</em> (liters).

Then the fraction of interest is (168 km)/(468 km), and it multiplies 117 L. The result is ...

... (168/468)×(117 L) = 42 L

1b. (10 h)/(4 h)×(138 mi) = 345 mi

2a. (180 mi)/(261 mi)×(15 h) ≈ 10.3448 h

2b. (4 h)/(5 h)×(452 km) = 362.6 km

You may have noticed that I keep the units with the numbers. When the same units are in the numerator and denominator, they cancel—the way any common factors cancel. The remaining units will be the units of the answer. This practice of keeping units with numbers can help ensure you're using the right numbers for the right purpose. If the units don't work out, your math has an error.

5a. (2 lb)/(50 lb)×$200 = $8

5b. (7 h)/(6 h)×381 km = 444.5 km

5c. (459 km)/(427 km)×(43 h) ≈ 46.2225 h

5d. (20 kg)/(11 kg)×$88 = $160

6 0
3 years ago
How do you do this I need help with this now
larisa86 [58]

Answer:

you have to do, x axis times y axis which should give you your answer.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
(Solving for a). b=(4*a)-3/4
Andrei [34K]

Answer:

a = 3/28

Step-by-step explanation:

<em>To start solving for a variable, you need to isolate it.</em>

-4/3b = 4a

<em>-4/3 divided by 4 equals -4/12 or </em><em>-1/3</em>

a = -1/3b

<em>To completely solve for </em><em>a</em><em> we need to plug it back in and solve for </em><em>b</em><em>.</em>

b = (4(-1/3b)) - 3/4

b = -4/3b - 3/4

7/3b = -3/4

b = -9/28

<em>Finally, we can plug </em><em>b</em><em> back in to the previous equation we got for </em><em>a</em><em> to solve for </em><em>a</em><em>.</em>

a = -1/3(-9/28)

a = 3/28

<em>Furthermore, we can check if this is correct by plugging in </em><em>3/28</em><em> for </em><em>a</em><em> into the original problem and see if we get what we got for </em><em>b</em><em> (</em><em>-9/28</em><em>)</em>

8 0
3 years ago
Please helppp with my geometry
stiks02 [169]

Answer:

a (-3,6)

b (6,9)

c (9,3)

Step-by-step explanation:

4 0
3 years ago
Describe the transformation of g(x) as it relates to the parent function f(x).
Jet001 [13]

Answer:

Hope this helps

Step-by-step explanation:

g(x)=f(x−h) g ( x ) = f ( x - h ) - The graph is shifted to the right h units. The vertical shift depends on the value of k . When k>0 , the vertical shift is described as: ... g(x)=f(x)−k g ( x ) = f ( x ) - k - The graph is shifted down k units.

6 0
2 years ago
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