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drek231 [11]
3 years ago
11

What is the most important long-lasting internal heat source responsible for geological activity?

Physics
1 answer:
egoroff_w [7]3 years ago
8 0

Answer::: the most important long-lasting internal heat source responsible for geological activity is called Radioactive decay

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Four balls have the same temperature. Which ball has the most thermal
puteri [66]

Answer:

a bowling ball because it has the most mass.

7 0
3 years ago
Read 2 more answers
Calculate the period of a spring if it has a mass of 5 kg and a spring constant of 6 N/m
otez555 [7]

Answer: The period of a spring if it has a mass of 5 kg and a spring constant of 6 N/m is 5.73 sec.

Explanation:

Given: Mass = 5 kg

Spring constant = 6 N/m

Formula used to calculate period is as follows.

T = 2 \pi \sqrt\frac{m}{k}

where,

T = period

m = mass

k = spring constant

Substitute the values into above formula as follows.

T = 2 \pi \sqrt\frac{m}{k}\\= 2 \times 3.14 \times \sqrt\frac{5}{6}\\= 5.73 s

Thus, we can conclude that the period of a spring if it has a mass of 5 kg and a spring constant of 6 N/m is 5.73 sec.

5 0
3 years ago
Please help !!!!! I’ll give brainliest !
goblinko [34]

I think A but I dont really know

3 0
3 years ago
A wire carries a steady current of 2.60 A. A straight section of the wire is 0.750 m long and lies along the x axis within a uni
ad-work [718]

Answer:

The magnetic force on the section of wire is -2.925\hat{j}\ N.

Explanation:

Given that,

Current I = 2.60\hat{i}\ A

Length = 0.750 m

Magnetic field B = 1.50\hat{k}\ T

We need to calculate the magnetic force on the section of wire

Using formula of magnetic force

\vec{F}=l\vec{I}\times\vec{B}

\vec{F}=0.750\times2.60\hat{i}\times1.50\hat{k}

Since, \hat{i}\times\hat{k}=-\hat{j}

\vec{F}=-2.925\hat{j}\ N

Hence, The magnetic force on the section of wire is -2.925\hat{j}\ N.

7 0
3 years ago
A force of 10. N toward the right is exerted on a wooden crate initially moving to the right on a horizontal wooden floor. the c
Artyom0805 [142]

1) 5 N

The crate is initially moving, so we must calculate the force of kinetic friction, which is given by:

F_f = \mu_k mg

where

\mu_k=0.2 is the coefficient of friction between the crate (made of wood) and the floor (made of wood). The coefficient of kinetic friction between wood and wood is about 0.2.

mg=25 N is the weight of the crate

Substituting the numbers into the formula, we find

F_f=(0.2)(25 N)=5 N


2) 5 N

There are two forces acting on the crate along the horizontal direction:

- The force that pushes the crate toward the right, of magnitude F=10 N

- The force of friction, which acts in the opposite direction (so, towards the left), of magnitude F_f = 5 N

Since the two forces are in opposite directions, the net force is given by their difference:

F_{net}=F-F_f = 10 N-5 N=5 N


3) Yes

The crate is accelerating. In fact, according to Second Newton's Law:

F_{net}=ma (1)

where Fnet is the net force on the crate, m is its mass, a is its acceleration. We can immediately see that since Fnet is not zero, the acceleration is also non-zero, so the crate is accelerating.

We can even calculate the magnitude of the acceleration. In fact, the mass of the crate is given by:

m=\frac{Weight}{g}=\frac{25 N}{9.8 m/s^2}=2.55 kg

And by using (1) we find

a=\frac{F_{net}}{m}=\frac{5 N}{2.55 kg}=1.96 m/s^2


3 0
3 years ago
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