Fusion and gravity is ur answer
Answer:
The required angular speed ω of an ultra-centrifuge is:
ω = 18074 rad/sec
Explanation:
Given that:
Radius = r = 1.8 cm
Acceleration due to g = a = 6.0 x 10⁵ g
Sol:
We know that
Angular Acceleration = Angular Radius x Speed²
a = r x ω ²
Putting the values
6 x 10⁵ g = 1.8 cm x ω ²
Converting 1.8 cm to 0.018 m, also g = 9.8 ms⁻²
6 x 10⁵ x 9.8 = 0.018 x ω ²
ω ² = (6 x 10⁵ x 9.8) / 0.018
ω ² = 5880000 / 0.018
ω ² = 326666667
ω = 18074 rad/sec
The results may differ due to resistive forces that may be affecting the system by decelerating it or any other external forces that might accelerate it a bit.Or the timing could be a little inaccurate.
Classically and Newtonianly, it's the sum of the chemical energy if any,
the electrical energy if any, the thermal energy if any, and the mechanical
energy consisting of potential and kinetic energy if any.
The mechanical energy, consisting of potential and kinetic energy if any, is
0.001 x [ (acceleration of gravity x height) + (1/2) (speed)² ] .
But I've got a sneaky hunch that you're not talking about any of these.
You want to know how much [ <em><u>mc</u>² </em>] there is in 1 gram of mass. No prob.
E = m c² = (0.001) x (3 x 10⁸)² = <em>9 x 10¹³ joules</em>
That's the energy that a 1,000-watt toaster uses
in <em>2,852 years</em> of continuous toasting.
