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Arada [10]
3 years ago
13

Find your mass if a scale on earth reads 650 N when you stand on it.

Physics
1 answer:
dezoksy [38]3 years ago
7 0

Weight = (mass) x (acceleration of gravity) .

On Earth, acceleration of gravity is 9.8 m/s² (rounded) .

                                                    650 N                 = (mass) x (9.8 m/s²)

Divide each side by (9.8 m/s²):    650 N / 9.8 m/s² = mass

                                                     Mass = 66.3 kilograms (rounded)

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During a __________ year period starting at about 4.5 billion years ago, bits and pieces of metal-rich particles, rocks, and ice
Greeley [361]

During a 30-10 million year period starting at about 4.5 billion years ago, bits and pieces of metal-rich particles, rocks, and ices accumulated to form the earth.

<h3>What is the Earth?</h3>

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3 0
1 year ago
A teacher pushed a 98 newton desk across a floor for a distance of 5 meters. He exerted a horizontal force of 20 N for four seco
Pie

Answer:

First let's find the work.

Work = Force*Displacement

= 20*5

= 100 Joules

Power = Work/Time

= 100/4

= 25 Watts

7 0
3 years ago
In an oscillating L C circuit, the maximum charge on the capacitor is 1.5 × 10 − 6 C and the maximum current through the inducto
Andre45 [30]

Answer:

T= 1.71×10^{-3} sec= 1.71 mili sec

t_{fc}= 4.281×10^{-4} sec or 0.4281 mili sec

Explanation:

First of all we write equation for current oscillation in LC circuits. Note, the maximum current (I_0)=  5.5 mA is the amplitude of this function. Then, we continue to solve for the angular frequency(ω). Afterwards, we calculate the time period T. qo = maximum charge on capacitor. = 1.5× 10 ^− 6 C

a) I(t) = -ωqosin(ωt+φ)

⇒Io= ωqo

⇒ω= Io/qo

also we know that T= 2π/ω

⇒T= 2\pi\frac{q_0}{I_0}

now putting the values we get

= 2\pi\frac{1.5\times10^{-6}}{5.5\times10^{-3}}

= 1.71×10^{-3} sec

b) note that the time t_{fc} it takes the capacitor to from uncharge to fully charged is one fourth of the period . That is

t_{fc}= \frac{T}{4}

t_{fc}= \frac{ 1.71\times10^{-3} }{4}

t_{fc}= 4.281×10^{-4} sec or 0.4281 mili sec

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3 years ago
What best describes a lens galaxy
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5 0
4 years ago
Read 2 more answers
a 25 kg object is pushed with a horizontal force of 5 N esat across a table. If the force of friction is 2 N, what is the accele
Julli [10]

Answer:

Apply Newton's second law in the moving direction.

Explanation:

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Friction force applies in the opposite direction of motion; as a restriction.

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