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KiRa [710]
3 years ago
15

Noaya already read 117 pages of his book for english class . Today he sits down to read the book at a rate of 55 pages per hour?

Mathematics
1 answer:
almond37 [142]3 years ago
7 0

if the question is how long it will take him to read the pages, the answer is the number of pages divided by the number of pages per hour.

117/55≈2.1273, so on average 2.13 hours to read all 117 pages

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Graph the function, identify if it represents exponential growth or decay, and identify domain and range. See picture
Brrunno [24]

Answer:

a. Decay

b. 0.5

c. 4

Explanation:

If we have a function of the form

y=ab^x

then

a = intital amount

b = growth / decay rate factor

x = time interval

If b > 1; then the equation is modelling growth. If b < 0, then the equation is modelling decay.

Now in our case, we have

y=4(\frac{1}{2})^x

Here we see that

inital amount = a = 4

b = 1/ 2 < 0, meaning the function is modeling decay

decay factor = b = 1/2

Therefore, the answers are

a. Decay

b. 0.5

c. 4

4 0
1 year ago
Which term describes a fraction that has a variable or variable expression in its numerator, its denominator, or both?
inna [77]
<span>The right answers is B. Rational expression.

This is true given that the statement establishes a term that describes a fraction that has a <em>variable or variable expression</em> in its numerator, denominator or both, that is, this is the concept of the quotient of two polynomials called rational expression. Finally, we can get the following rational expressions that matches with this concept, namely:

</span>(1) \ \frac{1}{x} \\ \\ (2) \ \frac{2x-1}{x+1} \\ \\ (3) \ \frac{x^{2}-1}{x^{2}+1}<span>
</span>
6 0
3 years ago
Read 2 more answers
Express 15x^1/3 y ^1/5 using a radical
9966 [12]

Answer:

C

Step-by-step explanation:

15x^{\frac{1}{3} }y^{\frac{1}{5} }\\\\=15x^{\frac{5*1}{5*3} }y^{\frac{3*1}{3*5} }\\\\=15x^{\frac{5}{15} }y^{\frac{3}{15} }\\\\=15\sqrt[15]{x^{5}y^{3} } \\\\

3 0
3 years ago
A recent study from the University of Virginia looked at the effectiveness of an online sleep therapy program in treating insomn
Ludmilka [50]

Answer:

1. The 99% confidence interval for the difference in average is -6.47377 < μ₁ - μ₂ < -11.34623

2. The possible issues in the calculations includes;

a. The confidence level used in the confidence interval can influence the result of the confidence interval observed

b. The sample size is small

Step-by-step explanation:

1. The number of adults with insomnia in the sample = 45

The number of adults that participated in the therapy, n₁ = 22

The number of candidates that served as control group, n₂ = 23

The average score for the for the 22 participants of the program, \overline x_1 = 6.59

The standard deviation for the 22 participants of the program, s₁ = 4.10

The average score for the for the 23 subjects in the control group, \overline x_2 = 15.50

The standard deviation for the 23 subjects in the control group, s₂ = 5.34

The confidence interval for unknown standard deviation, σ, is given by the following expression;

\left (\bar{x}_{1}- \bar{x}_{2}  \right )\pm t_{\alpha /2}\sqrt{\dfrac{s_{1}^{2}}{n_{1}}+\dfrac{s_{2}^{2}}{n_{2}}}

α = 1 - 0.99 = 0.01

α/2 = 0.005

The degrees of freedom, df = 22 - 1 = 21

t_{\alpha /2} = t_{0.005, \, 21} = 1.721

Therefore, we have;

\left (6.59- 15.5  \right )\pm1.721 \cdot \sqrt{\dfrac{4.10^{2}}{22}+\dfrac{5.34^{2}}{23}}

The 99% confidence interval for the difference in average is therefore given as follows;

-6.47377 < μ₁ - μ₂ < -11.34623

Therefore, there is considerable evidence that the participants in the survey  had lower average score than the subjects in the control group

2. The possible issues in the calculations are;

a. The confidence level used in the confidence interval can influence the result of the confidence interval observed

b. The sample size is small

5 0
2 years ago
Josefina hit a tennis ball into the air with an
max2010maxim [7]
7 = -16t2 + 16t + 3
7 = t2 + 3
7 -3 = t2 + 3 - 3
4 = t2
square root of 4 = square root of t2
2 = t
2 seconds
8 0
3 years ago
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