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sukhopar [10]
3 years ago
5

A column of soldiers, marching at 121 steps per minute, keep in step with the beat of a drummer at the head of the column. It is

observed that the soldiers in the rear end of the column are striding forward with the left foot when the drummer is advancing with the right. What is the approximate length of the column? (Take the speed of sound to be 343 m/s.)
Physics
1 answer:
Novay_Z [31]3 years ago
7 0

There’s a first “clump”/drum beat every half second. That clump will travel about 170m in half a second. Someone 170m away would do their “clump” as the second “clump” was taking place. I think. <span> </span>

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One horsepower is a unit of power equal to 746 W. How much energy can a 150 horsepower engine transform in 10.0 seconds
11111nata11111 [884]
1,119,000 basically 746 times 150 then multiply that answer by 10
7 0
3 years ago
Planet x has a mass of 4x1022 kg and a radius of 6x105 m What lise the grav ritational field strength in the surface of planet X
SCORPION-xisa [38]

Answer:

  g ≈ 7.4 m/s²

Explanation:

The acceleration due to gravity on planet XX is ...

  g = GM/r² = (6.67·10^-11 × 4·10^22)/(6·10^5)^2

  g ≈ 7.4 m/s²

6 0
2 years ago
In a Rutherford scattering experiment a target nucleus has a diameter of 1.34×10-14 m. The incoming α particle has a mass of 6.6
Rasek [7]

Answer:

E = 2.5 x 10⁻¹⁴ J

Explanation:

given,

diameter = 1.33 x 10⁻¹⁴ m

mass = 6.64 x 10⁻²⁷ kg

wavelength is equal to diameter

de broglie wavelength equal to diameter

         \lambda = \dfrac{h}{mv}

         1.33 \times 10^{-14}= \dfrac{6.626 \times 10^{-34}}{6.64 \times 10^{-27}\times v}

         v= \dfrac{6.626 \times 10^{-34}}{6.64 \times 10^{-27}\times 1.33 \times 10^{-14}}

              v = 7.5 x 10⁶ m/s

Kinetic energy is equal to

     E = \dfrac{1}{2}mv^2

     E = \dfrac{1}{2}\times 6.64 \times 10^{-27}\times (7.5\times 10^6)^2

            E = 2.5 x 10⁻¹⁴ J

8 0
3 years ago
7. A neutral aluminum rod is at rest on a foam insulating base. A negatively charged balloon is brought near one end of the rod
WITCHER [35]

Answer:

If a negatively charged balloon is brought near one end of the rod but not in direct contact, then <u>the negative charges on the balloon repel the same amount of negative charges on the end of the rod that is close to the balloon</u>, and the positive charges stay at the balloon-side of the rod. The total charge of the rod is still zero, but the distribution of the charges are now non-uniform.

6 0
3 years ago
Please help I'm stuck on this question ​
Afina-wow [57]

Answer:

increase

decrease

Explanation:

using formula

Vt=mg/6πηr

so if m increases V increases

r is the denominator so if r increases V decreases

8 0
2 years ago
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