A column of soldiers, marching at 121 steps per minute, keep in step with the beat of a drummer at the head of the column. It is
1 answer:
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Answer:
= 0.331 J / g ° C
Explanation:
We have a calorimetry exercise where all the heat yielded by one of the components is absorbed by the other.
Heat ceded Qh = m1 ce1 ( -
)
Heat absorbed Qc = m2 ce2 ( - T₀)
Body 1 is metal and body 2 is water . Where m are the masses of the two bodies, ce their specific heat and T the temperatures
Qh = Qc
m₁ (
-
) = m₂
(
- T₀)
we clear the specific heat of the metal
= m₂
(
- T₀) / (m₁ (
-
))
= 50.00 4.184 (20.15 -10.79) / (75.00 (99.0-20.15))
= 209.2 (9.36) / (75 78.85)
= 1958.11 / 5913.75
= 0.331 J / g ° C
Answer:
Explanation:
we know angular velocity in terms of moment of inertia and angular speed
ω .... (1)
moment of inertia of rod rotating about its center of length b
........ .(2)
using v = ωr
where w is angular velocity
and r is radius of rod which is equal to b
so we get 2v = ωb
ω = 2v/b ................. (3)
here velocity is two time because two opposite ends are moving opposite with a velocity v so net velocity will be 2v
put second and third equation in ist equation
×
so final answer will be