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2 years ago

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A column of soldiers, marching at 121 steps per minute, keep in step with the beat of a drummer at the head of the column. It is

observed that the soldiers in the rear end of the column are striding forward with the left foot when the drummer is advancing with the right. What is the approximate length of the column? (Take the speed of sound to be 343 m/s.)

1 answer:

Novay_Z [31]2 years ago

7 0

There’s a first “clump”/drum beat every half second. That clump will travel about 170m in half a second. Someone 170m away would do their “clump” as the second “clump” was taking place. I think. <span> </span>

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Use complete sentences to differentiate between acids and bases on the basis of their behavior when dissolved in water Give an e

grigory [225]

Explanation:

An acid is a substance that interacts with water to produce excess hydroxonium ions, H₃O⁺ in an aqueous solution.

The hydroxonium ions formed by the chemical bonding between the oxygen of water molecules and the protons released by the acid due to its excess ionization.

For example:

HCl + H₂O ⇄ H₃O⁺ + Cl⁻

acid water hydroxonium chloride

A base is a substance that interacts with water to yield excess hydroxide ions, OH⁻ in an aqueous solutions:

NH₃ + H₂O ⇄ NH₄⁺ + OH⁻

Ammonia water ammonium hydroxide

These explanations are based on the arrhenius theory.

learn more:

Bronsted-lowry theory brainly.com/question/4083753

Acid reaction brainly.com/question/5273689

#learnwithBrainly

4 0

2 years ago

Jesse travels 3.0 meters east and then turns and travels 4.0 meters north. What distance did Jesse travel?

arsen [322]

Answer:

7.0 meters, not 7.0 meters NE

Explanation:

It is 7.0 meters because you add the two distances together and he wasn't going NE, he just turned north after traveling east.

Hope this helps!

(Can I please get brainliest, I really really want one!!!!)

5 0

2 years ago

Consider the binding energy of two stable nuclei, one with 60 nucleons and one with 200 nucleons. a. Is the total binding energy

sashaice [31]

Answer:

The total binding energy of the nucleus with 200 nucleons more than the total binding energy of the nucleus with 60 nucleons

Explanation:

Binding energy can be given by the formula:

Binding energy = Binding energy per nucleon * Number of nucleons

This means that if the binding energy per nucleon = x MeV

Where x is a positive real number

The nucleus with 60 nucleons will have Binding energy = 60x MeV

The nucleus with 200 nucleons will have binding energy = 200x MeV

For a +ve x, 200x > 60x

4 0

3 years ago

Consider a system to be one train car moving toward another train car at rest. When the trains collide, the two cars stick toget

pickupchik [31]

As per the question, the system consists of two cars.

The the masses of two cars are denoted as- $m_{1} \ and\ m_{2} \ respectively$

The two cars undergoes collision with each other. Here collision must be inelastic in nature.

Let the velocities of each car is denoted as- $v_{1} \ and\ v_{2} \ respectively$

It is given that masses of two cars and initial velocities-

$m_{1} =600 kg$ $v_{1} =4m/s$

$m_{2} = 400kg$ $v_{2} =0 m/s$

First we have to calculate the total momentum of the system before collision.

The momentum of a body is the product of its mass with velocity.

Momentum of car 1:

$p_{1} =m_{1} v_{1}$

$=600kg*4m/s$

$=2400\ kg\ m\ s^-1$

The momentum of car 2:

$p_{2} =m_{2} v_{2}$

$=400\ kg*0\ m/s$

$=\ 0\ kg\ m\ s^-1$

Now the total momentum of the system is :

$p_{1} +p_{2}$

$=[2400+0]\ kg\ m\ s^-1$

$=2400\ kg\ m\ s^-1$

Now we are asked to calculate the total momentum of the system after collision.

The basic condition in case of any type of collision is that it is in accordance with law of conservation of linear momentum.

Hence, the momentum will be conserved here.

It means the total momentum before collision must be equal to the total momentum after collision.

Hence, the correct answer to the question will be 2400 kg m/s.

8 0

2 years ago

Read 2 more answers

A plastic rod 1.6 m long is rubbed all over with wool, and acquires a charge of -9e-08 coulombs. We choose the center of the rod

Gekata [30.6K]

Solution :

Length of the plastic rod , L = 1.6 m

Total charge on the plastic rod , Q = $-9 \times 10^{-8}$ C

The rod is divided into 8 pieces.

a). The length of the 8 pieces is , $l=\frac{L}{8}$

$=\frac{1.6}{8}$

= 0.2 m

b). Location of the center of the piece number 5 is given as : 0 m, -0.09375 m, 0 m.

c). The charge q on the piece number 5 is given as

$q=\frac{Q}{L}\times l$

$q=\frac{-9 \times 10^{-8}}{1.6}\times0.2$

= $-1.125 \times 10^{-8}$ C

d). WE approximate that piece 5 as a point charge and we need to find out the field at point A(0.7 m, 0, 0) only due to the charge.

We know, the Coulombs force constant, k = $8.99 \times 10^9 \ N.m^2/C^2$

So the X component of the electric field at the point A is given as

$E_x = 8.99 \times 10^9 \times 1 \times 10^{-8} \ \cos \frac{187.628}{0.70625}$

= -126.15 N/C

The Y component of the electric field at the point A is

$E_y = 8.99 \times 10^9 \times 1 \times 10^{-8} \ \sin \frac{187.628}{0.70625}$

= -16.93 N/C

Now since the rod and the point A is in the x - y plane, the z component of the field at point A due to the piece 5 will be zero.

∴ $E_z=0$

Thus, $E=$

3 0

2 years ago