Answer:
Explanation:
Given
mass of tree stump is 
mass bullet is 
velocity of bullet is 
Conserving momentum for bullet and tree stump
Initial Momentum 
Suppose
is the velocity of the system
Final Momentum 
Initial momentum =Final Momentum


Answer:
a
The orbital speed is 
b
The escape velocity of the rocket is 
Explanation:
Generally angular velocity is mathematically represented as
Where T is the period which is given as 1.6 days = 
Substituting the value


At the point when the rocket is on a circular orbit
The gravitational force = centripetal force and this can be mathematically represented as

Where G is the universal gravitational constant with a value 
M is the mass of the earth with a constant value of 
r is the distance between earth and circular orbit where the rocke is found
Making r the subject
![r = \sqrt[3]{\frac{GM}{w^2} }](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7BGM%7D%7Bw%5E2%7D%20%7D)
![= \sqrt[3]{\frac{6.67*10^{-11} * 5.98*10^{24}}{(4.45*10^{-5})^2} }](https://tex.z-dn.net/?f=%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B6.67%2A10%5E%7B-11%7D%20%2A%205.98%2A10%5E%7B24%7D%7D%7B%284.45%2A10%5E%7B-5%7D%29%5E2%7D%20%7D)

The orbital speed is represented mathematically as

Substituting value

The escape velocity is mathematically represented as

Substituting values


Answer:
Explanation:
M = 1.989 x 10^30 kg
R = 6.96 x 10^8 m
G = 6.67 x 10^-11 Nm²/kg²
Let the velocity is v.


v = 6.17 x 10^5 m/s
Answer:
To the right relative to the original frame.
Explanation:
In first reference frame <em>S</em>,
Spatial interval of the event, 
Temporal interval of the event, 
In the second reference frame <em>S'</em>, the two flashes are simultaneous, which means that the temporal interval of the event in this frame is 
The speed of the frame <em>S' </em>with respect to frame <em>S</em> = v.
According to the Lorentz transformation,

And positive v means the velocity of the second frame<em> </em><em>S'</em> is along the positive x-axis direction, i.e., to the right direction relative to the original frame <em>S</em>.