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3 years ago

A person is standing 110m below the top of cliff B, and thetwo

Physics

1 answer:

kondor19780726 [428]3 years ago

3 0

Answer:

8.86m/s

Explanation:

The attachment below contain the explanation and answer

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A completely submerged object always displaces its own

Rom4ik [11]

Mass value/Weight. This is expalined in archamedies principle

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4 years ago

Gravity causes___ objects to accelerate

kolbaska11 [484]

Gravity causes falling objects to accelerate.

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4 years ago

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Collette has a prediction that college students ' immune systems have declined due to the use of hand sanitizers . This idea is

Nataly_w [17]

The idea that "students ' immune systems have declined due to the use of hand sanitizers " is a hypothesis.

The term hypothesis refers to an intelligent guess or idea often based which is subject to scientific investigation via experiments.

A hypothesis may be right or wrong. We can only prove a hypothesis by subjecting it to a series of rigorous experiments.

Thus Collette's idea is a hypothesis.

Learn more: brainly.com/question/18284466

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3 years ago

wide tube that extends down from the bag of solution, which hangs from a pole so that the fluid level is 90.0 cm above the needl

Bingel [31]

Answer:

The average gauge pressure inside the vein is 110270.58 Pa

Explanation:

This question can be solved using the Bernoulli's Equation. First, in order to determine the outlet pressure of the needle, we need to find the total pressure exerted by the atmosphere and the fluid.

$P_f: fluid's\ pressure\\P_f= \rho g h=1025\frac{kg}{m^3} \times 9.8 \frac{m}{s^2} \times 0.9 m=9040.5 Pa \\P_T: total\ pressure\\P_T=P_{atm}+P_f\\P_T=101325 Pa + 9040.5 Pa=110275.5 Pa\\$

Then, we have to find the fluid's outlet velocity with the transversal area of the needle, as follows:

$S: transversal\ area \\S= \pi r^2=\pi (0.200 \times 10^{-3})^2=5.65 \times 10^{-7} m^2\\v=\frac{F}{S}=\frac{5.55 \times 10^{-8} \frac{m^3}{s}}{5.65 \times 10^{-7} m^2}=0.98\times 10^{-1} \frac{m}{s}$

As we have all the information, we can complete the Bernoulli's expression and solve to find the outlet pressure as follows:

$P_T-P_{out}=\frac{1}{2} \rho v^2\\P_{out}=P_T-\frac{1}{2} \rho v^2=110275.5 Pa-\frac{1}{2} 1025\frac{kg}{m^3} (0.98\times 10^{-1} \frac{m}{s})^2=110275.5 Pa-4.92 Pa =110270.58 Pa$

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3 years ago

Need help asap if I fail this one I fail my grade so please tell me the right awser

bazaltina [42]

If you look up "distance vs time graph" you can pull up images on google and check them out. That's what I did and on the x-axis (horizontal line) it said "time." I'd go with time.

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3 years ago