Question

A pendulum that has a period of 2.67000 s and that is located where the acceleration due to gravity is 9.77 m/s2 is moved to a location where it the acceleration due to gravity is 9.81 m/s2. What is its new period? (Enter your answer in seconds and to at least 5 decimal places.)

Answer 1

Answer:

Explanation:

Expression for time period of pendulum is given as follows

$T=2\pi\sqrt{\frac{l}{g} }$

where l is length of pendulum and g is acceleration due to gravity .

Putting the given values for first place

$2.67=2\pi\sqrt{\frac{l}{9.77} }$

Putting the values for second place

$T=2\pi\sqrt{\frac{l}{9.81} }$

Dividing these two equation

$\frac{T}{2.67} =\sqrt{\frac{9.77}{9.81} }$

T = 2.66455 s.