The period of oscillation of the system is 12.56 s
Explanation:
The period of oscillation of a spring-mass system is given by

where
m is the mass attached to the spring
k is the spring constant
For the system in this problem, we have
m = 40 kg
k = 10 N/m
Substituting into the equation, we find

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Answer:
Explanation:
we have to make charge inside the conductor zero because we know that electric field inside the conductor should be zero
so, the outer surface of the conductor should contain + 10 uC of charge and the inner surface contains -10 uC
625 /5=125/5=25/5=5
1000/5=200/5=40/5=8
is 5 Over 8