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VLD [36.1K]
3 years ago
10

8. A car moving at 35 m/s has 675 joules of KE. What is the mass of the car?

Physics
1 answer:
andreyandreev [35.5K]3 years ago
6 0
Kinetic energy is the energy possessed by a body in motion while potential energy is the energy of a body at rest.
Kinetic energy is given by E=1/2MV² where M is the mass of the body while V is the velocity of the body. 
To get mass we can use the formula M= 2 Ek/V² (Making M the subject)
hence mass  = (2 ×675)÷35²
                     = 1.102 kg 
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Answer:

C. The car from driving off the road on a curve

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From the following statements about mechanical waves, identify those that are true for transverse mechanical waves only, those t
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'In transverse waves, the particles of the medium move perpendicular to the direction of the flow of energy' is true for transverse waves only.

'In longitudinal waves, the particles of the medium move parallel to the direction of the flow of energy' is true for longitudinal waves only.

'Many wave motions in nature are a combination of longitudinal and transverse motion' is true for both longitudinal and transverse waves.

<u>Explanation:</u>

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As wave motions are assumed to be of standing waves which comprises of particles moving parallel as well as perpendicular to the medium, most of the wave motions are composed of longitudinal and transverse motion.

So the option stating the medium' particle moves perpendicular to the direction of the energy flow is true for transverse waves. Similarly, the option stating the medium' particle moves parallel to the direction of flow of energy is true for longitudinal waves only.

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5 0
2 years ago
A student uses the circuit shown to determine the resistance of two identical resistors.
Ivanshal [37]

Answer:

B. 0.552

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determine the force of gravitational attraction between a 78kg boy sitting 2 meters away from a 65kg girl.
bixtya [17]

Answer:

F=8.45\times 10^{-8}\ N

Explanation:

Given that,

Mass of a boy is 78 kg

Mass of a girl is 65 kg

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The formula for the gravitational force is given by :

F=\dfrac{Gm_1m_2}{r^2}\\\\F=\dfrac{6.67\times 10^{-11}\times 78\times 65}{(2)^2}\\\\=8.45\times 10^{-8}\ N

So, the force between them is 8.45\times 10^{-8}\ N.

8 0
2 years ago
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