Answer:
r = 58.44 [m]
Explanation:
To solve this problem we must use the following equation that relates the centripetal acceleration with the tangential velocity and the radius of rotation.
a = v²/r
where:
a = centripetal acceleration = 15.4 [m/s²]
v = tangential speed = 30 [m/s]
r = radius or distance [m]
r = v²/a
r = 30²/15.4
r = 58.44 [m]
Answer:
The height is 3.1m
Explanation:
Here we have a conservation of energy problem, we have a conversion form eslastic potencial energy to gravitational potencial energy, so:

then we have only gravitational potencial energy when the ball is at its maximun height.

because all the energy was transformed Eg=Ee

searching the web, the mass of a ping pong ball is 2.7 gr in average. so:

Given :
Liquid is poured into a burrete so that it reads 14cm³.
50 drops were run each of volume 0.1cm³ .
To Find :
The volume of liquid in burrete after 50 drops.
Solution :
Volume of each drop, v = 0.1 cm³.
Initial volume in burrete, V = 14 cm³.
Now, volume left after droping 50 drops are :

Therefore, the volume left in burrete is 9 cm³ .