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Juli2301 [7.4K]
3 years ago
5

What do contour lines on a topographic map show? location of game trails lakes and rivers roads and highways elevation of the gr

ound?
Physics
1 answer:
Lina20 [59]3 years ago
3 0
<span>Contour lines on a topographic map show elevation of the ground. Contour lines on a map that are constructed by connecting points of equal elevation .
</span><span>
</span><span>some general characteristics of contour lines:
</span><span>1) They do not cross each other, split or divide.
</span><span>2) Steep slopes are reprented by contour lines spaced closely. Gentle slopes are reprented by contour lines spaced far apart
</span><span>3) Contour lines trend up valleys and form a "V" or a "U" where they cross a stream.</span>
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How far will you have traveled on a bus driving 31 m/s for 3 hours.
ryzh [129]
Well, isn’t v=d/t, then by making subject d, d=vt, turn 3 hours into seconds, 1hr=3600sec, hence 3hr=x, cross multiply and you would have converted it into seconds, then put it into your equation of d=vt
3 0
3 years ago
Select the correct answer. In a given chemical reaction, the energy of the products is greater than the energy of the reactants.
ioda
B. Energy is released in the reaction... just looked it up!
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3 years ago
How much work does this force do as the particle moves along the x-axis from x = 0 to x = l? express your answer in terms of the
nydimaria [60]
<h3><u>Answer</u>;</h3>

= F0 L ( 1 - 1/e )

<h3><u>Explanation;</u></h3>

Work done is given as the product of force and distance.

In this case;

Work done  = ∫︎ F(x) dx  

                    = F0 ∫︎ e^(-x/L) dx  

                    = F0 [ -L e^(-x/L) ] between 0 and L  

                    = F0 L ( 1 - 1/e )

3 0
4 years ago
To practice Problem-Solving Strategy 11.1 Equilibrium of a Rigid Body. A horizontal uniform bar of mass 2.7 kg and length 3.0 m
Zanzabum

Answer:

T_{1} = 14.88 N

Explanation:

Let's begin by listing out the given variables:

M = 2.7 kg, L = 3 m, m = 1.35 kg, d = 0.6 m,

g = 9.8 m/s²

At equilibrium, the sum of all external torque acting on an object equals zero

τ(net) = 0

Taking moment about T_{1} we have:

(M + m) g * 0.5L - T_{2}(L - d) = 0

⇒ T_{2} = [(M + m) g * 0.5L] ÷ (L - d)

T_{2} = [(2.7 + 1.35) * 9.8 * 0.5(3)] ÷ (3 - 0.6)

T_{2}= 59.535 ÷ 2.4

T_{2} = 24.80625 N ≈ 24.81 N

Weight of bar(W) = M * g = 2.7 * 9.8 = 26.46 N

Weight of monkey(w) = m * g = 1.35 * 9.8 = 13.23 N

Using sum of equilibrium in the vertical direction, we have:

T_{1} + T_{2} = W + w   ------- Eqn 1

Substituting T2, W & w into the Eqn 1

T_{1} + 24.81 = 26.46 + 13.23

T_{1} = <u>14.88</u> N

8 0
3 years ago
(BRAINLIEST!) Does more momentum mean more force?
evablogger [386]

Answer:

no.

Explanation:

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3 years ago
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