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Rudik [331]
3 years ago
15

What is the approximate size of the smallest object on the earth that astronauts can resolve by eye when they are orbiting 250 k

m above the earth? assume λ = 500 nm and a pupil diameter of 5.00 mm?
Physics
1 answer:
Alex17521 [72]3 years ago
5 0
<span>Skipping OTF and considering a small angle, then 2.38E5 • 1.22(4.56E-7/2.2E-3): 60 meters.</span>
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A tennis ball is dropped from 1.16 m above the
sweet-ann [11.9K]

Answer:

Vf = 4.77 m/s

Explanation:

During the downward motion we can easily find the final velocity or the velocity with which the ball hits the ground, by using third equation of motion. The third equation of motion is given as follows:

2gh = Vf² - Vi²

where,

g = acceleration due to gravity = 9.8 m/s²

h = height = 1.16 m

Vf = Final Velocity of Ball = ?

Vi = Initial Velocity of Ball = 0 m/s (Since, ball was initially at rest)

Therefore, using these values in the equation, we get:

(2)(9.8 m/s²)(1.16 m) = Vf² - (0 m/s)²

Vf = √(22.736 m²/s²)

<u>Vf = 4.77 m/s</u>

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3 years ago
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nlexa [21]

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Here,

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When the position is at the equilibrium point (x = 0), the speed will be maximum, and could even be expressed as

v_{max}= A\sqrt{\frac{x}{m}}

So the correct answer is B.

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