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cestrela7 [59]
2 years ago
8

Suppose the coordinate of P is 2, PQ = 8, and PR = 12. What are the possible coordinates of the midpoint of the given segment? T

he coordinates are PQ, PR, and QR.. . So confused on how to do this.. please help!! :)
Mathematics
1 answer:
Ratling [72]2 years ago
3 0
Base in your question the coordinate is P is 2, PQ has a coordinate of 8 while PR has a coordinate of 12. To find the mid point of each segment you must first find the coordinate of QR which is from 8-12. So the answer will be 
PQ = 5, PR = 6, and QR= 10
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Answer:

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Step-by-step explanation:

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2 years ago
When rolling two six faced dice, what is the probability the sum equal to seven?
Liono4ka [1.6K]
What you want is P(6∩1) or P(1∩6) or P(2∩5) or P(5∩2) or P(3∩4) or P(4∩3).
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5 0
3 years ago
Use the parabola tool to graph the quadratic function f(x)=(x-5)^2+1
andrey2020 [161]

Answer:

Look to the attached graph

Step-by-step explanation:

* Lets revise how to graph the quadratic function

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- The completing square form for any quadratic is

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* Lets compare the two forms

∵ (x - h)² + k = (x - 5)² + 1

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- To find the y-intercept put x = 0

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3 years ago
The ratio x:y is equal to 2:3 express x in terms of y
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Answer:

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7 0
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Read 2 more answers
Derive the formula for the area of a sector, and then use it to choose all that are correct.
Marina CMI [18]

Answer:

Part A) A_s=\frac{\pi r^{2}}{360^o}{\theta}

Part B) option 1,option 4

Step-by-step explanation:

Part A) Derive the formula for the area of a sector

we know that

The area of circle is equal to

A=\pi r^{2}

The area of circle subtends a central angle of 360 degrees

so

using proportion

Find out the area of a sector  A_s  by a central angle of ∅ degrees

\frac{\pi r^{2}}{360^o}=\frac{A_s}{\theta}

A_s=\frac{\pi r^{2}}{360^o}{\theta}

Part B) Verify each case

case 1) we have

radius = 5 cm

angle = 120°

area = 26.2 cm 2

Find the area of the sector and then compare with the value of the given area

assume

\pi=3.14

substitute the given values

A_s=\frac{(3.14)(5)^{2}}{360^o}{120^o}

A_s=26.2\ cm^2

so

The given value of area is correct

case 2) we have

radius = 4 cm

angle = 105°

area = 16.7 cm 2

Find the area of the sector and then compare with the value of the given area

assume

\pi=3.14

substitute the given values

A_s=\frac{(3.14)(4)^{2}}{360^o}{105^o}

A_s=14.7\ cm^2

so

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case 3) we have

radius = 6 cm

angle = 85°

area = 23.7 cm 2

Find the area of the sector and then compare with the value of the given area

assume

\pi=3.14

substitute the given values

A_s=\frac{(3.14)(6)^{2}}{360^o}{85^o}

A_s=26.7\ cm^2

so

The given value of area is not correct

case 4) we have

radius = 7

angle = 75°

area = 32.1 cm 2

Find the area of the sector and then compare with the value of the given area

assume

\pi=3.14

substitute the given values

A_s=\frac{(3.14)(7)^{2}}{360^o}{75^o}

A_s=32.1\ cm^2

so

The given value of area is correct

5 0
3 years ago
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