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Alex787 [66]
3 years ago
5

Between what pair of numbers is the product of 289 and 7

Mathematics
1 answer:
Colt1911 [192]3 years ago
3 0
289 X 7 = 2023

2022 2023 2024

2023 IS BETWEEM 2022 AND 2024 (:
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Find the slope of the points (2, 13) and (8, 1)
Pie
-2

y2-y1/x2-x1
take the y coordinate of the second pair of coordinates and subtract it by the y coordinate of the first pair, then take the x coordinate from the second pair of coordinates and subtract it from the x coordinate from the first pair. then put your answer from the y coordinate over the answer from the x coordinates. 1 - 13 / 8 - 2, then you get -12/6, which simplifies to 2.

Hope this helps :)
5 0
3 years ago
In (triangle symbol)ABC, (angle symbol)C is a right angle. Find the remaining sides and angles. Round your answers to the neares
irinina [24]
Use the Pythagorean Theorem.

a² + b² = c²

3² + b² = 19²

9 + b² = 361

b² = 352

b = 4√11

Now, solve for the remaining angles by using the trigonometric ratios:

Sine = opposite/hypotenuse

sin(A)= 3/19

sininverse(3/19) = 9.1 = angle A

180-9.1-90 = 80.9 = angle B


3 0
3 years ago
The following problem has a mistake in it. Correct the right side:<br> 7(a+2)=7xa+2
Nadya [2.5K]
Answer:
7(a+2) = 7a+14
Explanation:
Distribution Formula
5 0
3 years ago
A bag holds 5.8lb of corn. How many pounds do 2.5 bags hold
gayaneshka [121]

ANSWER:

14.5 pounds

STEP-BY-STEP EXPLANATION:

We know the capacity of each bag, therefore, we can calculate the capacity of 2.5 bags, multiplying by the capacity of one, like this:

\begin{gathered} c=5.8\cdot2.5 \\  \\ c=14.5\text{ lb} \end{gathered}

Which means 2.5 bags contain a total of 14.5 lbs.

3 0
1 year ago
Find the exact value of the following expression (without using a calculator): tan(Sin^-1 x/2)
Sati [7]

Answer:

tan(Sin^-1 x/2)=  \frac{x/2}{\sqrt{1-x^{2}/4 } }

Step-by-step explanation:

Let sin^-1 x/2= θ

then sinθ= x/2

on the basis of unit circle, we have a triangle with hypotenuse of length 1,   one side of length x/2 and opposite angle of θ.

          tan(Sin^-1 x/2) = tanθ

           tanθ= sinθ/cosθ

as per trigonometric identities cosθ= √(1-sin^2θ)

           tanθ= sinθ/ √(1-sin^2θ)

substituting the value sinθ=x/2 in the above equation

             tanθ= \frac{x/2}{\sqrt{1-x^{2}/4 } }

now substituting the value sin^-1 x/2= θ in above equation

             tan(sin^-1 x/2) =  \frac{x/2}{\sqrt{1-x^{2}/4 } }

!

3 0
3 years ago
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