All categories

4 years ago

2abc-3ab if a=2 b= -3 c=4

Mathematics

2 answers:

34kurt4 years ago

8 0

Most likely -30 but dont hold me to it

NemiM [27]4 years ago

8 0

2(2)(-3)(4)-3(2)(-3)
(4)(-12)-3(-6)
-48+18
-30

You might be interested in

Solve as many as you can please

Dmitry_Shevchenko [17]

Answer:

1. 135

2. 114

3. .19

4. 170

5. 336

6. 106.25

7. No, the associative property does not work for subtraction or division, they do not hold for the associative property. For example,

2+ (3+4) = (2+3) + 4 2- (3-4) = (2-3) – 4

2+7 = 5+4 2 + 1 = -1-4

9 = 9 3 = -5, which is not true

8. No, the commutative property does not work for subtraction or division, they will give a different result. For example,

5+6 = 6+5 5-6 ≠ 6-5

3 0

3 years ago

What kind of boundary line represents an inequality that is < or >

ladessa [460]

Answer:

Step-by-step explanation:

Dotted line.

5 0

3 years ago

The coordinates of point A on a coordinate grid are (−2, −3). Point A is reflected across the y-axis to obtain point B and acros

Levart [38]

B= (2,-3)
c= (2, 3)
i believe that's the answer

3 0

3 years ago

If x = 2 + V3, then the value of (x + 1/x) is

ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given

x + $\frac{1}{x}$ ← substitute x = 2 + $\sqrt{3}$

= 2 + $\sqrt{3}$ + $\frac{1}{2+\sqrt{3} }$

Rationalise the denominator of the fraction by multiplying the numerator/ denominator by the conjugate of the denominator.

The conjugate of 2 + $\sqrt{3}$ is 2 - $\sqrt{3}$ , thus

= 2 + $\sqrt{3}$ + $\frac{2-\sqrt{3} }{(2+\sqrt{3} )(2-\sqrt{3}) }$

= 2 + $\sqrt{3}$ + $\frac{2-\sqrt{3} }{4-3}$

= 2 + $\sqrt{3}$ + 2 - $\sqrt{3}$

= 4

6 0

3 years ago

The monthly electrical utility bills of all customers for the Far East Power and Light Company are known to be normally distribu

omeli [17]

Answer: 0.9996

Step-by-step explanation:

Given : The monthly electrical utility bills of all customers for the Far East Power and Light Company are known to be normally distributed with a mean $\mu=$\ 87.00$

Standard deviation : $\sigma=$\ 36.00$

Sample size : n=100

Let X be the random variable that represents the electricity utility bill for a randomly selected month .

z-score : $z=\dfrac{X-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

For X = $75.00

$z=\dfrac{75.00-87.00}{\dfrac{36}{\sqrt{100}}}\approx-3.33$

Now, the probability that the average bill for those sampled will exceed $75.00 will be :-

$P(X>75)=P(z>-3.33)=1-P(z\leq-3.33)\\\\=1- 0.0004342=0.9995658\approx0.9996$

Hence, the probability that the average bill for those sampled will exceed $75.00 =0.9996

3 0

4 years ago