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Vlad [161]
3 years ago
5

Given: 2x+13=1 Prove: x = 1 Select from the drop-down menus to correctly complete the proof. Statement Reason 2x+13=1 Given 2x+1

=3 Choose... 2x = 2 Choose... x = 1 Choose...
Mathematics
1 answer:
HACTEHA [7]3 years ago
4 0

The value of x from the equation is 1

Given the equation 2x + 1 = 3

We are to find the value of x as shown:

Step 1: Subtract 1 from both sides

2x + 1 - 1 = 3  - 1 (Subtraction property of equality)

2x  = 2

Step 2: Divide both sides by 2:

2x/2 = 2/2 (Division property of equality)

x = 1

Hence the value of x from the equation is 1

Learn more here: brainly.com/question/2159099

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What is the circumference of this circle?
Cerrena [4.2K]

Answer:

12.5663

Step-by-step explanation:

circumference = pi x diameter

d= 2r

d = (2)2

d=4

c=4pi

c=12.5663

4 0
3 years ago
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One number is eight less than another. The sum of the numbers is 24
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Answer:

32

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a-8=24

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2 years ago
Use the parabola tool to graph the quadratic function f(x)=(x−4)(x+2). Graph the parabola by first plotting its vertex and then
Andrew [12]

Answer: erm... the vertex it (1,-9)

Step-by-step explanation:

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3 years ago
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Cans of lemonade and packets of crisps were bought for the school disco in the ratio 3:2. The organiser bought 120 cans of lemon
koban [17]
120 dived by 3 multiplied by 2 is equal to 80 packs of crisps 
4 0
3 years ago
What is the length of the hypotenuse triangle if both sides are 36
vovikov84 [41]

Answer:

<h3>\boxed{ \bold{ \huge{ \boxed{ \sf{36 \sqrt{2}  \:  \:  units}}}}}</h3>

Step-by-step explanation:

Given,

Perpendicular ( P ) = 36

Base ( b ) = 36

Hypotenuse ( h ) = ?

<u>Finding</u><u> </u><u>the </u><u>hypotenuse </u> :

<u>Using </u><u>the </u><u>Pythagoras </u><u>theorem</u><u> </u>:

\sf{ {h}^{2}  =  {p}^{2}  +  {b}^{2} }

plug the values

⇒\sf{ {h}^{2}  =  {36}^{2}  +  {36}^{2} }

Evaluate the power

⇒\sf{ {h}^{2}  = 1296 + 1296}

Add the numbers

⇒\sf{ {h}^{2}  = 2592}

Squaring on both sides

⇒\sf{h = 36 \sqrt{2} } units

Hope I helped!

Best regards!!

7 0
3 years ago
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