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Agata [3.3K]
3 years ago
14

Anna and Henry are raking their yard. Anna has raked 5/12 of the yard and Henry has raked 4/9 of the yard. What fraction of the

yard still
needs to be raked?
Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
6 0

Answer:

Step-by-step explanation:

The raked portion is 5/12 plus 4/9, or (applying the LCD, 36),

20/36 + 24/36.

The sum of these two fractions is 44/36, or 1/9.

1/9 of the yard remains to be raked.

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Answer:

x ≈ 14.4

Step-by-step explanation:

using the cosine ratio in the right triangle

cos59° = \frac{adjacent}{hypotenuse} = \frac{x}{28} ( multiply both sides by 28 )

28 × cos59° , then

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4 0
2 years ago
8 + 3x=29 +2x <br> I need answer ASAP
borishaifa [10]

Answer:

x = 21

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8 + 3x = 29 + 2x

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3 years ago
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4 years ago
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3 years ago
Will is twice as old as Jill. Three years ago, Jill's age was two fifths of Will's age then. How old is each now?
dimulka [17.4K]
"Will is twice as old as Jill."

                       Jill's age . . . . .   J
                       Will's age . . . . 2J .

"Three years ago . . .

                       Jill's age then . . . . .   J - 3
                       Will's age then . . . . 2J - 3

". . . Jill's age then was 2/5 of Will's age then."

                                         J - 3  =  (2/5) (2J - 3)
Multiply
each side by  5 :          5J - 15  =  2 (2J - 3)

Divide
each side by  2 :          2.5 J - 7.5  =  2J - 3 

Subtract  2J
from each side:            0.5 J - 7.5  =      -3

Add  7.5
to each side:                0.5 J           =     4.5

Multiply
each side by  2 :                J            =       9

Jill is  9  y.o. now.
Will is 18 y.o. now.

4 0
3 years ago
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