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jonny [76]
3 years ago
15

Find the​ range, variance, and standard deviation for the given sample data. Include appropriate units in the results. Listed be

low are the measured radiation absorption rates​ (in W/kg) corresponding to various cell phone models. If one of each model is measured for radiation and the results are used to find the measures of​ variation, are the results typical of the population of cell phones that are in​ use? 0.83 1.39 1.39 1.03 0.66 1.26 1.39 1.18 1.41 1.19 1.15
Mathematics
1 answer:
Sliva [168]3 years ago
5 0

Answer:

Range =1.41-0.66 = 0.75

\bar X = 1.171 W/Kg

s^2 = 0.0607

And taking the square root we got the sample deviation:

s = \sqrt{0.0607}= 0.246 W/kg

Step-by-step explanation:

For this case we have the following datset given:

0.83 1.39 1.39 1.03 0.66 1.26 1.39 1.18 1.41 1.19 1.15

We need to find the range, and the range is defined by:

Range = Max -Min

And replacinng we got:

Range =1.41-0.66 = 0.75

Then we can find the sample variance, but firt we need to find the sample mean with this formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And replacing we got:

\bar X = 1.171 W/Kg

Now we can find the sample variance with this formula:

s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}

And replacing we got:

s^2 = 0.0607

And taking the square root we got the sample deviation:

s = \sqrt{0.0607}= 0.246 W/kg

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Solving the quadratic function, it is found that the range is of:

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