Answer:
a) 5 N b) 225 N c) 5 N
Explanation:
a) Per Coulomb's Law the repulsive force between 2 equal sign charges, is directly proportional to the product of the charges, and inversely proportional to the square of the distance between them, acting along the line that joins the charges, as follows:
F₁₂ = K Q₁ Q₂ / r₁₂²
So, if we make Q1 = Q1/5, the net effect will be to reduce the force in the same factor, i.e. F₁₂ = 25 N / 5 = 5 N
b) If we reduce the distance, from r, to r/3, as the factor is squared, the net effect will be to increase the force in a factor equal to 3² = 9.
So, we will have F₁₂ = 9. 25 N = 225 N
c) If we make Q2 = 5Q2, the force would be increased 5 times, but if at the same , we increase the distance 5 times, as the factor is squared, the net factor will be 5/25 = 1/5, so we will have:
F₁₂ = 25 N .1/5 = 5 N
True.
The more the coils either at the Primary or Secondary coils, the higher the Primary or Secondary Emf. The lower the coils at the Primary or Secondary coils, the lower the EMF at the Primary or Secondary.
Hence there is a direct relationship.
Since the connection is in series, the current divider can be used. It's mathematical expression is In = (It Rt) / Rn. If the value for is solved, power dissipation can also be solved using P = I^2 R.
I = 0.47 A
A. P = (0.47)^2 (5) = 1.11 Watts
B. P = (0.47)^2 (9) = 2 Watts
C. P = VI = 16(0.47) 4.24 Watts
A vaccum unlike sound,light can travel through any matter including a great vacuum of nothing (space)
The area under the graph. W = f d cos(theta), so you want the number that is force times displacement, which corresponds to the area under the graph.
