Answer:
find the diagram in the attachment.
Explanation:
Let vi = 12 m/s be the intial velocy when the ball is thrown, Δy be the displacement of the ball to a point where it starts returning down, g = 9.8 m/s^2 be the balls acceleration due to gravity.
considering the motion when the ball thrown straight up, we know that the ball will come to a stop and return downwards, so:
(vf)^2 = (vi)^2 + 2×g×Δy
vf = 0 m/s, at the highest point in the upward motion, then:
0 = (vi)^2 + 2×g×Δy
-(vi)^2 = 2×g×Δy
Δy = [-(vi)^2]/2×g
Δy = [-(-12)^2]/(2×9.8)
Δy = - 7.35 m
then from the highest point in the straight up motion, the ball will go back down and attain the speed of 12 m/s at the same level as it was first thrown
We know that:
1 mile = 1.61 km
1 gal = 3.8 L
Therefore converting the fuel efficiency rates:
highway = (28.5 km/L) * (1 mile / 1.61 km) * (3.8 L / 1
gal) = 67.27 mile / gal
<span>city = (22.0 km/L) * (1 mile / 1.61 km) * (3.8 L / 1 gal)
= 51.93 mile / gal</span>
<span>The forces of nature are phase forces.</span>
Number one- numbers of items sold. Number two- Thursday and Friday. Number three- 1,200. Number four-150
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