Answer:
Whether the force exerted by the locomotive on the wall was larger
Than the force the locomotive could exert on the wall.
Explanation:
The Newton's third law of motion States that every force have it's equal and opposite reaction force, whose magnitude is the same as the applied force. Therefore the magnitude of these opposite forces will be equal.
So we have;
F12=-F21
F12 is the force in a direction
-F21 is the force in the opposite direction.
Therefore we see that the magnitude of the force the locomotive exerts on the wall is equal to the one the wall exerts on the locomotive. Both magnitudes are equal but in opposite directions.
The density of silver is ρ = 10500 kg/m³ approximately.
Given:
m = 1.70 kg, the mass of silver
t = 3.0 x 10⁻⁷ m, the thickness of the sheet
Let A be the area.
Then, by definition,
m = (t*A)*ρ
Therefore
A = m/(t*ρ)
= (1.7 kg)/ [(3.0 x 10⁻⁷ m)*(10500 kg/m³)]
= 539.7 m²
Answer: 539.7 m²
Answer:
20.996 m
Explanation:
Given:
Initial velocity, 
Final velocity, 
Total time taken, 
s.
∴ Acceleration is given as,
m/s²
Now, using Newton's equation of motion, we find the displacement.
Displacement is given as:
Plug in 0 for 
, 4.91257 for 
and 1.74 for 
. Solve for 
.
This gives,
Therefore, the train's displacement in the first 4.91257 s of motion is 20.996 m.
When boat is sunk into the liquid the net buoyancy on the boat is counterbalanced by weight of the boat
So here weight of the boat = Buoyancy force
let say boat is sunk by distance "h"
now we can say
now by above force balance equation we can write
so boat will sunk by total 5 mm distance
