Answer:
41°
Explanation:
refractive index of glass, n = 1.52
For total internal reflection, the angle of refraction in rarer medium is 90°.
r = 90°
Let the angle of refraction in denser medium, that means in glass is i.
By use of Snell's law
refractive index of rarer medium with respect to denser medium, that means refractive index of air with respect to glass = 1 / n
And
i = 41°
Thus, the angle of incidence should be 41°.
Answer:
a) W = 180.87 J , b) ΔU = -180.87 J , c) ΔU = -180.87 J
Explanation:
a) Work is defined as
W = F .ds
Where bold indicates vectors, we can write the scalar product
W = F s cos θ
Where the angle is between force and displacement.
The force of gravity is the weight of the body, which is directed downwards and the displacement thickens the tip of the cliff at the bottom, so that it is directed downwards, therefore the angle is zero degrees
W = y
W = m g y
For this problem we must fix a reference system, from the statement it is established that the system is placed at the base of the cliff, so that final height is zero and the initial height (y₀ = 7.69m)
W = 2.40 9.8 (7.69-0)
W = 180.87 J
b) The potential energy is
U = mg y
The change in potential energy,
ΔU = - U₀
ΔU = mg (- y₀)
ΔU = 2.4 9.8 (0 -7.69)
ΔU = -180.87 J
c) in this case we change the reference system to the height of the cliffs, for this configuration
y₀ = 0
= -7.69 m
ΔU = 2.4 9.8 (-7.69 -0)
ΔU = -180.87 J