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Lorico [155]
3 years ago
11

A bald eagle's average speed is about 50 km/h. About how long would it take an eagle to fly 1 kilometer? A. 1 second B. 1 minute

C. 1 hour D. 1 day
Chemistry
1 answer:
ANEK [815]3 years ago
5 0
B. About 1 minute. We can solve this a few different ways and it mostly depends on how you want to go about it. First, we set up the equation as:

distance traveled (x) = time traveled (y)

Since the eagle is going 50 km/hr, we can substitute these variables in.

50 kilometers = 1 hour

Now, neither of these numerical values help us get to the answer, because we want to figure out:

1 kilometer traveled = ?? time traveled.

From the original equation we know to be true, 50 km = 1 hr, we can divide both sides by 50 to convert 50 kilometers to 1 kilometer, and of course, we have to keep the equation balanced, so we divide 1 hr by 50 as well.

50/50 km = 1/50 hr

Solve to:

1 km = 0.02 hr

This is closer to a minute than any other answer when you convert 0.02 hours to minutes (roughly one minute and 12 seconds).
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Once of the skills necessary for this experiment is dilution. If you have 1.95 mL of .806 M bleach, what will be the new concent
aleksley [76]

<u>Answer:</u> The concentration of diluted bleach solution is 0.0157 M

<u>Explanation:</u>

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated bleach solution

M_2\text{ and }V_2 are the molarity and volume of diluted bleach solution

We are given:

M_1=0.806M\\V_1=1.95mL\\M_2=?M\\V_2=100mL

Putting values in above equation, we get:

0.806\times 1.95=M_2\times 100\\\\M_2=\frac{0.806\times 1.95}{100}=0.0157M

Hence, the concentration of diluted bleach solution is 0.0157 M

6 0
4 years ago
1.364mol of H2, 0.682mol of S2 and 0.680mol of H2S were mixed in a 2.00L container at 580°C. At equilibrium the concentration of
kenny6666 [7]

Answer: equilibrium constant = 2.576

3 0
3 years ago
In atoms, electrons surround the nucleus in?
Charra [1.4K]

either the answer is  B or D

4 0
3 years ago
Read 2 more answers
how does the total mass of each object increases the amount of force that is needed to get them moving at 5 m/s increase by abou
irakobra [83]

Answer:

The answer is below

Explanation:

Newton's second law of motion states that the force applied to an object is directly proportional to the rate of change of momentum with respect to time, going in the same direction as the force.

Let F = force, m = mass of object, v = velocity of object, mv = momentum.

F = d/dt(mv) = m(dv / dt) = ma; a = acceleration.

Let us assume that the object starts from rest to 5 m/s within 1 seconds, hence:

F = m(dv / dt)

200 N = m[(5 m/s - 0 m/s) / (1 s)]

200 = 5m

m = 40 kg

7 0
3 years ago
A bowling ball has a mass of 10.0kg. If a net force of 35N is applied to the ball, what’s the acceleration?
Paraphin [41]

Answer:

Acceleration =  3.5 m.s⁻²

Explanation:

Definition:

The acceleration is rate of change of velocity of an object with respect to time.

Formula:

a = Δv/Δt

a = acceleration

Δv = change in velocity

Δt = change in time

Units:

The unit of acceleration is m.s⁻².

Acceleration can also be determine through following formula,

F = m × a

a = F/m

Given data:

Force = 35 N  (N = Kg. m.s⁻²)

Mass = 10.0 Kg

a = ?

Formula:

a = F/m

a = 35 Kg. m.s⁻²/ 10.0 Kg

a =  3.5 m.s⁻²

3 0
4 years ago
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