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3 years ago

What type of change is the process of solid ice changing into liquid water?

Chemistry

2 answers:

stealth61 [152]3 years ago

6 0

I believe it is a physical change.

romanna [79]3 years ago

4 0

It is a physical change since there is no new product that is evolved.

It is not exothermic as it doesn’t give out heat, it absorbs heat (it is endothermic).

It is not ionic as it is not related to bonds.
It’s just H2O in both cases.

It is not a chemical change as there is no new product evolved.

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Lanthanium found in the......... period

Gnesinka [82]

I'm preatty sure it is in the periodic table xxx

5 0

3 years ago

In a typical analysis, 15 ml of an aqueous solution containing an unknown amount of acetylcholine had a ph of 7.65. When incubat

melomori [17]

pH of the acetyl choline solution before incubation = 7.65

$[H_{3}O^{+}]=10^{-7.65}=2.24*10^{-8}M$

pH of the solution after incubation = 6.87

$[H_{3}O^{+}]=10^{-6.87}=1.35*10^{-7}M$

The difference in concentration of hydronium ion before and after incubation

= $1.35*10^{-7}M$ - $2.24*10^{-8}M$ = $1.126*10^{-7}M$

This difference in hydronium ion concentration can be attributed to the increase in the concentration of acetic acid, which is formed when acetylcholine is hydrolyzed by acetycholinesterase. The mole ratio of acetylcholine to acetic acid is 1:1.

Therefore the moles of acetylcholine = $15 mL * \frac{1L}{1000mL}*\frac{1.126*10^{-7}mol }{L}=1.689*10^{-9}mol$

7 0

3 years ago

Help me pls!!!!!!!!!!!!!!!

tankabanditka [31]

The answer is: 2 NH3 —> N2 + 3 H2

6 0

2 years ago

Which of the following is needed to determine the molar mass of a<br> molecule?

jenyasd209 [6]

Answer:

atomic mass

Explanation:

5 0

2 years ago

Kf(water) = -1.86 °C/m In a laboratory experiment, students synthesized a new compound and found that when 13.39 grams of the co

zysi [14]

Answer:

The molecular weight for the compound is 60.1 g/mol

Explanation:

We need to determine the molality of solute to find out the molar mass of it.

We apply the colligative property of freezing point depression:

ΔT = Kf . m . i

If the compound was also found to be nonvolatile and a non-electrolyte,

i = 1.

Freezing T° of pure solvent - Freezing T° of solution = Kf . m

0°C - (-2.05°C) = 1.86°C/m . m

2.05°C / 1.86m/°C = m → 1.10 mol/kg

To determine the moles of solute we used, we can multiply molality by the mass of solvent in kg → 202.1 g . 1kg/1000g = 0.2021 kg

1.10 mol/kg . 0.2021kg = 0.223 moles

Molar mass→ g/mol → 13.39 g / 0.223 mol = 60.1 g/mol

5 0

3 years ago