Answer:
Explanation:
You most likely lost 1000 points because you cheated to get them if not there is a possibility you were.
Answer:
C code for half()
#include<stdio.h>
void half(float *pv);
int main()
{
float value=5.0; //value is initialized
printf ("Value before half: %4.1f\n", value); // Prints 5.0
half(&value); // the function call takes the address of the variable.
printf("Value after half: %4.1f\n", value); // Prints 2.5
}
void half(float *pv) //In function definition pointer pv will hold the address of variable passed.
{
*pv=*pv/2; //pointer value is accessed through * operator.
}
- This method is called call-by-reference method.
- Here when we call a function, we pass the address of the variable instead of passing the value of the variable.
- The address of “value” is passed from the “half” function within main(), then in called “half” function we store the address in float pointer ‘pv.’ Now inside the half(), we can manipulate the value pointed by pointer ‘pv’. That will reflect in the main().
- Inside half() we write *pv=*pv/2, which means the value of variable pointed by ‘pv’ will be the half of its value, so after returning from half function value of variable “value” inside main will be 2.5.
Output:
Output is given as image.
Answer:
There is no value of the number variable, for which the loop can be true in any iteration.
Explanation:
- The above loop states the condition that the value should be less than 100 and greater than 500. It is because the loop holds the and condition which gives the true if both conditions will be true.
- The first condition of the while loop states that the value of the number variable is less than the 100.
- The second condition of the while loop state that the value of the number variable is greater than the 500.
- The and condition of the while loop will true if both conditions will true.
- But there is no number which is less than 100 and greater than 500.
- So no number can satisfy the while condition to be true.
Answer:
The most likely galaxy type to be identifiable regardless of orientation is: Irr
Explanation:
The Irr galaxies don't have a discernable or usual shape; that is why it is relatively easy to identify.
When we talk about E type galaxies, this statement proves itself by the way the cumulus of stars compounds the galaxy. The elliptical galaxies have the form of ellipses, with a reasonable distribution of stars. The degree of eccentricity is the number that complements the E letter; that's why E0 galaxies are almost spherical, while E7 is considerably elongated.
SBc, SBa galaxies are spiral; this means it can be flat in some angles difficulting their identification process; in this case, the last letter means the way the arms display their form, with "c" having a vague form and "a" well-defined arms. That's why in some angles can be mistreated as another type of galaxy.
Answer:
The question is a bit unclear. Are you asking how to add these values in this 2D array?
Explanation:
