If y=x+2 were changed to y=x-1 how would the graph of the new function compare with the first one

Find the midpoint and distance between each pair of points, with easy explanation and work !! will give brainliest.

rewona [7]

If we have 2 coordinates say: (x1,y1) and (x2,y2)

Then the formula for the midpoint is:

((x1+x2)/2,(y1+y2)/2)

And the formula for the distance is:

Sqrt((x2-x1)^2+(y2-y1)^2)

So here we have (-1,-4) and (-7,4)

The midpoint is:

((-1+-7)/2,(-4+4)/2) = (-8/2,0/2) = (-4,0)

The distance is:

Sqrt((-7- -1)^2+(4- -4)^2)
= sqrt((-6^2)+(8^2))
=sqrt(36+64)
=sqrt(100)
=10

6 0

3 years ago

Es 18 de junio de 1815, las tropas napoleónicas se encuentran justo adelante, tu eres el ingeniero en balística y el general Wel

Airida [17]

Answer:

89.1° or -1.4°

Step-by-step explanation:

1. Location:

You are on the Mont-Saint-Jean escarpment, near the Belgian town of Waterloo.

The French troops are about 50 m below you and 1.2 km distant.

2. Finding the firing angle

Data:

R = 1200 m

u = 600 m/s

h = -50 m (the height of the target)

a = 9.8 m/s²

We have two conditions.

Horizontal distance

(1) 1200 = 600t cosθ

Vertical distance

(2) -50 = 600t sinθ - 4.9t²

Divide each side of (1) by 600cosθ.

$(3) \, t =\dfrac{2}{\cos \theta}$

Substitute (3) into (2)

$-50 = 600t \sin \theta - 4.9t^{2} = 600 \left( \dfrac{2}{\cos \theta} \right ) \sin \theta - 4.9 \left( \dfrac{2}{\cos \theta} \right )^{2}\\\\(4) \, -50 = 1200 \tan \theta - \dfrac{19.6}{\cos^{2} \theta}$

Recall that

(5) sec²θ = 1/cos²θ = tan²θ + 1

Substitute (5) into (4)

$-50 = 1200 \tan \theta - 19.6 \left(\tan^{2} \theta}+ 1\right )$

Set up a quadratic equation

$\begin{array}{rcl}-50 & = & 1200 \tan \theta - 19.6\tan^{2} \theta -19.6 \\0 & = & 1200 \tan \theta - 19.6\tan^{2} \theta + 30.4\\0 & =&19.6\tan^{2} \theta - 1200 \tan \theta - 30.4\\0 & =&\tan^{2} \theta - 61.224 \tan \theta - 1.551\\\end{array}$

Solve for θ

Use the quadratic formula.

tanθ = 61.249 or -0.025

θ = arctan(61.249) = 89.1° or

θ = arctan(-0.025) = -1.4°

3 0

3 years ago

Not sure if I did this correctly... please help 3. Is the one I'm kinda stuck on

denis23 [38]

You got the b part wrong. It would be 4B+4C/2=4D

6 0

3 years ago

Read 2 more answers

An investment firm invested in two companies last year. They invested $40,000 in company A and made a profit of 15%. They invest

alexira [117]

Answer:

A) $8200.

B) 16.4%

Step-by-step explanation:

Here is the complete question: An investment firm invested in two companies last year. They invested $40,000 in company A and made a profit of 15%. They invested $10,000 in company B and made a profit of 22%.

A) What is the investment firms total profit?

B) What is the percent profit of the total investment?

Given: Company A invested $40000 and made profit of 15%

Company B invested $10000 and made profit of 22%

A) First lets find the profit of company A and B.

Company A= $\frac{15}{100} \times \$ 40000= \$ 6000.$