Answer:
y= 34/23
x= 123/46
Step-by-step explanation:
Solve for x
8x-5y= 14
x= 14/8 +5/8y
Sub x into second equation
– 5х+бу = -3
-5(14/8 +5/8y) + 6y= -3
-29/4 +23/8y = -3
y= 34/23
Sub y into any equation and solve for x
8x=483/23
x= 123/46
Answer:
4w+120.
Step-by-step explanation:
She downloads 4 songs for every week which is represented as 4w, and she started with 120 songs which is represented as +120.
Answer:
a. has one solution
b. infinite solution
Step-by-step explanation:
a.
2(x - 1) + 6 = 4x - 22
2x - 2 + 6 = 4x - 22
2x - 4x = 2 - 6 - 22
-2x = -26
x = 26/2
x = 13
b.
6(2x + 1) – 2 = 12x + 4
12x + 6 - 2 = 12x + 4
12x - 12x = 4 + 2 - 6
0 = 0
Answer:
tanΘ = - 
Step-by-step explanation:
Using the trigonometric identity
tan²Θ + 1 = sec²Θ, thus
tan²Θ + 1 = (
)² = 
( subtract 1 from both sides )
tan²Θ = 
( take the square root of both sides )
tanΘ = ± 
Since 270 < Θ < 360 , that is the fourth quadrant where tan Θ < 0, thus
tanΘ = -
Complete Question
Let P (n) be the statement that a postage of n cents can be formed using just 4-cent stamps and 7-cent stamps. The parts of this exercise outline a strong induction proof that P (n) is true for n ≥ 18.
Show statements P (18), P (19), P (20), and P (21) are true, completing the basis step of the proof.
Answer:
P(18) is true
P(19) is true
P(20) is true
P(21) is true
Step-by-step explanation:
a. When n = 18
18 cents can be formed using two 7cents and one 4cents
i.e. 2 * 7 + 4 = 18
So, P(18) is true
b. When n = 19
19 cents can be formed using one 7cents and three 4cents
i.e. 1 * 7 + 3 * 4 = 19
So, P(19) is true
c. When n = 20
18 cents can be formed using five 4cents
i.e. 5 * 4 = 20
So, P(20) is true
d. When n = 21
18 cents can be formed using three 7cents
i.e. 3 * 7 = 21
So, P(21) is true
