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Firlakuza [10]
3 years ago
9

Write the equation in slope intercept form ( y=mx+b )

Mathematics
2 answers:
In-s [12.5K]3 years ago
7 0

Answer:

y=-4x-3

Step-by-step explanation:

I hope this is correct and have a great day

Katarina [22]3 years ago
6 0
It’s y=-4x -3 yr welcome
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Please help in integral calculus
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Answer:

-2x(5x²-6)

Step-by-step explanation:

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Help pleaseeeeee<br><br> 4x (-3/8)=
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Answer:

-3x/2

Step-by-step explanation:

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3 years ago
The spinner is equally likely to land on any of the six sections. a spinner contains 6 equal sections: 1, 2, 3, 4, 5, 6. section
tangare [24]

The probability that the spinner will land on a number greater than 4 or on a shaded section is five-sixt

<h3>What is probability?</h3>

Probability is the likelihood or chance that an event will occur. Mathematically;

Probability = Expected/Total

If the spinner is spinned, the total outcome is 1/6

Pr(greater than 4) = 2/6 = 1/3

Pr(shaded section) = 3/6 = 1/2

Pr(number greater than 4 or on a shaded section) = 1/3 + 1/2
Pr(number greater than 4 or on a shaded section)  = 5/6

Hence the probability that the spinner will land on a number greater than 4 or on a shaded section is five-sixths

Learn more on probability here: brainly.com/question/25870256

5 0
2 years ago
You deposit $5000 in a bank account that pays 3.5% annual
miskamm [114]

Answer:

Its A i just took the test

Step-by-step explanation:

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3 years ago
solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations. x-2y+
Alekssandra [29.7K]

Answer:

x = -5, y = -6, z = -3

Step-by-step explanation:

Given the system of three equations:

\left\{\begin{array}{l}x-2y+3z=-2\\6x+2y+2z=-48\\x+4y+3z=-38\end{array}\right.

Write the augmented matrix for the system of equations

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)

Find the reduced row-echelon form of the augmented matrix for the system of equations:

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)\sim \left(\begin{array}{ccccc}1&-2&3&|&-2\\0&-14&16&|&36\\0&-6&0&|&36\end{array}\right)\sim \left(\begin{array}{ccccc}1&3&-2&|&-2\\0&16&-14&|&36\\0&0&-6&|&36\end{array}\right)

Thus, the system of three equations is

\left\{\begin{array}{r}x+3z-2y=-2\\16z-14y=36\\-6y=36\end{array}\right.

From the last equation:

y=-6

Substitute it into the second equation:

16z-14\cdot (-6)=36\\ \\16z=36-84\\ \\16z=-48\\ \\z=-3

Substitute y = -6 and z = -3 into the first equation:

x+3\cdot (-3)-2\cdot (-6)=-2\\ \\x=-2+9-12\\ \\x=-5

7 0
3 years ago
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