The cold-blooded animals need to bask in sunshine before they can move as quickly as warm-blooded animals on a cold day because it increases their rate of metabolism.
<h3>What are cold-blooded animals?</h3>
Cold-blooded animals are those animals that are not able to regulate and maintain their internal body temperature when there is change in the external environment.
Example of cold-blooded animals are snakes and turtles. They expose themselves to sunlight to help them with their body metabolism.
Therefore, the cold-blooded animals need to bask in sunshine before they can move as quickly as warm-blooded animals on a cold day because it increases their rate of metabolism.
Learn more about metabolism here:
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Answer:
A - DNA
B - mRNA
C - nuclear pore
D - tRNA
E - ribosome
F - rRNA
Explanation:
<em>The entire structure illustrates the process of transcription and translation in a typical eukaryotic cell.</em>
The DNA (A) in the nucleus of the cell is first transcribed to mRNA (B). The mRNA produced is transported to the cytoplasm through the openings within the nuclear membrane - the nuclear pores (C). On getting to the cytoplasm, the mRNA binds to the ribosome (E) (carrying rRNA, F). The tRNA (D) carrying the specific anticodon for a particular codon on the mRNA then binds to the structure and the corresponding amino acid is released. A polypeptide bond is formed between subsequent amino acids and the ribosome moves along the mRNA chain until the translation process is complete.
Firstly they are not membranes and they are villi's which increase the surface area during digestion
Is there suppose too be a photo attached because if so it’s not
Answer:
0.058 % kcalories comes from carbohydrate.
Explanation:
1 g of carbohydrtes gives 4 calories, 1 g of protein gives 4 kcalories, 1 gm of fat gives 9 calories and 1 g of alcohol gives 7 calories of energy.
Thus in a meal that contains 110 g carbohydrates gives 110 x 4 = 440 calories, 25 g protein gives 25 x 4 = 100 calories, 20 g fat gives 20 x 9 = 180 calories and 5 g alcohol gives 5 x 7 = 35 calories.
Total calories in a meal 440+100+180+35 = 755.
Therefore % of carbogydrate will be 440x 100 divided by 755 = 58.27 %
In kcalories % would be 58.27/1000 = 0.5827 %
