Answer:
<h2>Recombination rate or recombination frequency between locus A and locus C is either 2% or 50%.
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Explanation:
As given,
Recombination frequency between locus A and B is 35%, means that the distance between A and B is 35 cM.
Recombination frequency between locus B and C is 33% , means the distance between B and C is 33 cM.
Therefore, if the locus C is present between A and B, then the recombination frequency between A and C would be 2%
A-----C ----------B
A---C= 2%
A----B= 35%
B---C= 33%
So, here the recombination frequency between A and C is 2%, means their distance is 2 cM.
If the locus C is as, A---35---B--33----C ; A-----B------C
A-----B= 35%
B------C= 33%
A-----C= 33+35= 68%
As rule, maximum frequency can not exceed 50%, as here the Recombination frequency between A and C = 50%.
Answer:
They are ammonia, urea, uric acid, and creatinine. All of these substances are produced from protein metabolism.
Metabolic waste is the left over products of both catabolism and anabolism. This waste includes salts, phosphates, sulfates, excess substances, and nitrogenous wastes like urea which are eliminated through urine.
Answer:
the answer is always wear safety goggles
It is because the enzymes in the plant are breaking down cellulose.
Grouse species have evolved living in environments with little vertical structure and in areas with minimum human activity (from roads and cultivation to other more complex infrastructure). In the recent decades, there has been a significant increase in wind energy development in diverse areas and ecosystems. This development involves construction and placement of tall man-made structures, such as wind turbines and other infrastructure in habitats with high wind capacity. These habitats are often occupied by grouse species. This coexistence could severely endanger the species survivorship and reproductive ability. It is very important to study grouse habitat selection and demography, so that appropriate regulatory guidelines can be applied to wind energy development.
