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Sav [38]
3 years ago
13

a 0.784 g sample of magnesium is added to a 250 ml flask and dissolved in 150ml of water. magnesium hydroxide obtained from the

reaction required 215.0 mL of 0.300 M hydrochloric acid to completely react. How many moles of Mg were used?
Chemistry
1 answer:
Svetach [21]3 years ago
5 0

The chemical reaction involving Mg(OH)2 and HCl is:

<span>Mg(OH)2  +  2HCl  -->  MgCl2  +  2H2O</span>

 

So we see that for every 2 moles of HCl, 1 mole of Mg is reacted.

Calculating for moles HCl:

moles HCl = 0.300 M * 0.215 L

moles HCl = 0.0645 mol

 

The moles Mg then is:

moles Mg = 0.0645 mol * (1 / 2)

<span>moles Mg = 0.03225 mol</span>

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