Ca + 2HCl = CaCl₂ + H₂
c=4.50 mol/l
v=2.20 l
n(HCl)=cv
m(Ca)/M(Ca)=n(HCl)/2
m(Ca)=M(Ca)cv/2
m(Ca)=40g/mol·4.50mol/l·2.20l/2=198 g
198 grams of Ca are needed
0.500 moles is roughly .5*6.022*10^23=3.011*10^23 atoms. This is independent of STP.
Answer:
<u>mnemonic</u><u> </u><u>isjdndbeudxhdnrhcurhrfkrr</u>
Option a: alkene
Styren is C6H5CH=CH2, i.e. ethenylbenzene
