You have molarity and you have volume. Use the formula :
Molarity(M)= Moles(N)/Liter(L) to get the solution.
150 ml= .150 L
7.7 = N/.150
N=.1.155 moles of NaOH.
And since you know the moles, use the molar mass to figure out the grams.
<span> (40g/mol NaOH) x (1.155mol) =
46.2 g of NaOH.</span>
Answer:
O2 is limiting reactant
Explanation:
To find the limiting reactant we need to convert the mass of each reactant to the moles using the formula weight. And, as 1 mole of C6H12O6 reacts with 6 moles of O2, we can know wich reactant will be over first (Limiting reactant) as follows:
<em>Moles C6H12O6:</em>
650g * (1mol/180.16g) = 3.608 moles C6H12O6
<em>Moles O2:</em>
650g * (1mol/32g) = 20.31 moles O2
Now, for a complete reaction of 3.608 moles of C6H12O6 are required:
3.608 moles C6H12O6 * (6mol O2 / 1mol C6H12O6) = 21.65 moles O2
As there are just 20.31 moles of O2,
<h3>O2 is limiting reactant</h3>
Hello!
Your answer would be polar covalent.
Covalent bonds are where two atoms come together, and share electrons between each other, and are therefore, bonded.
In some cases of molecules that are bonded with a covalent bond, one of the atoms is more, you could call it selfish, and takes more of the electrons. A prime example of this is H20, or water. One of the atoms takes the electrons for longer, and therefore has a more negative charge because electrons are counted as negative charges.
This bond where an atom "hogs" electrons, is called a polar covalent bond, respective to the changing charges for the atoms.
So your answer is d.
Hope this helped!
Answer: -
Following are five examples of structures with the chemical formula C₆H₁₂
Compound A is Hexene.
Compound B is 2-Hexene.
Compound C is 3-Hexene.
Compound D is Cyclohexane.
Compound E is Methylcyclopentane.
As we can see Hexene, 2- Hexene and 3-Hexene all have double bonds.
Cyclohexane and Methylcyclopentane contains a ring.
Answer:
3 to 4 days is how long you can keep cooked beef in the refrigerator
