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OverLord2011 [107]
3 years ago
6

How many moles are in 6.8 x 10^23 molecules of NaOH? (show work please)

Chemistry
1 answer:
alexdok [17]3 years ago
3 0

Answer:

1.13moles

Explanation:

no. of molecules,N= 6.8 x 10^23

Avogadro's constant, L= 6.02 x 10^23

no. of moles=N/L

=6.8 x 10^23/6.02 x 10^23

=1.13moles

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A metal sample weighing 129.00 grams and at a temperature of 97.8 degrees Celsius was placed in 45.00 grams of water in a calori
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Answer : The specific heat of metal is 0.481J/g^oC.

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of metal = ?

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T_2 = initial temperature of water = 20.4^oC

Now put all the given values in the above formula, we get

129.00g\times c_1\times (39.6-97.8)^oC=-45.00g\times 4.184J/g^oC\times (39.6-20.4)^oC

c_1=0.481J/g^oC

Therefore, the specific heat of metal is 0.481J/g^oC.

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How many moles of AIC3 are there in 1,119.972 g ?
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