This dilution problem uses the equation
M
a
V
a
=
M
b
V
b
M
a
= 6.77M - the initial molarity (concentration)
V
a
= 15.00 mL - the initial volume
M
b
= 1.50 M - the desired molarity (concentration)
V
b
= (15.00 + x mL) - the volume of the desired solution
(6.77 M) (15.00 mL) = (1.50 M)(15.00 mL + x )
101.55 M mL= 22.5 M mL + 1.50x M
101.55 M mL - 22.5 M mL = 1.50x M
79.05 M mL = 1.50 M
79.05 M mL / 1.50 M = x
52.7 mL = x
59.7 mL needs to be added to the original 15.00 mL solution in order to dilute it from 6.77 M to 1.50 M.
I hope this was helpful.
This is not chemistry but
see it is a triangular prim on it's side
V=BH
are of base times height
the base is a triangle
height is 18.5
base=1/2bh
b=8.6
h=8.4
base=1/2(8.6)(8.4)
base=36.12
V=bh
V=36.12*18.5
V=668.22
round
V=668.2 ft^3
Both <span>b) the weight of jelly beans and c) elevation of a person on a ramp</span>
These are called resistors.
