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OverLord2011 [107]
3 years ago
6

How many moles are in 6.8 x 10^23 molecules of NaOH? (show work please)

Chemistry
1 answer:
alexdok [17]3 years ago
3 0

Answer:

1.13moles

Explanation:

no. of molecules,N= 6.8 x 10^23

Avogadro's constant, L= 6.02 x 10^23

no. of moles=N/L

=6.8 x 10^23/6.02 x 10^23

=1.13moles

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<u>Explanation:</u>

We are given:

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So, mole fraction of C_2H_4 = 0.3

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We know that:

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To calculate the average molecular mass of the mixture, we use the equation:

\text{Average molecular weight of mixture}=\frac{_{i=1}^n\sum{\chi_im_i}}{n_i}

where,

\chi_i = mole fractions of i-th species

m_i = molar masses of i-th species

n_i = number of observations

Putting values in above equation:

\text{Average molecular weight}=\frac{(\chi_{CH_4}\times M_{CH_4})+(\chi_{C_2H_4}\times M_{C_2H_4})+(\chi_{C_2H_2}\times M_{C_2H_2})+(\chi_{C_2H_2O}\times M_{C_2H_2O})}{4}

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Hence, the correct answer is Option d.

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