Answer:
it is possible to remove 99.99% Cu2 by converting it to Cu(s)
Explanation:
So, from the question/problem above we are given the following ionic or REDOX equations of reactions;
Cu2+ + 2e- <--------------------------------------------------------------> Cu (s) Eo= 0.339 V
Sn2+ + 2e- <---------------------------------------------------------------> Sn (s) Eo= -0.141 V
In order to convert 99.99% Cu2 into Cu(s), the equation of reaction given below is needed:
Cu²⁺ + Sn ----------------------------------------------------------------------------> Cu + Sn²⁺.
Therefore, E°[overall] = 0.339 - [-0.141] = 0.48 V.
Therefore, the change in Gibbs' free energy, ΔG° = - nFE°. Where E° = O.48V, n= 2 and F = 96500 C.
Thus, ΔG° = - 92640.
This is less than zero[0]. Therefore, it is possible to remove 99.99% Cu2 by converting it to Cu(s) because the reaction is a spontaneous reaction.
Answer:
0.0249 moles in 1 g of Ca
Explanation:
Let's think in the molar mass of Ca.
Ca = 40.08 g/mol
So 1 mol weighs 40.08 grams, or in the opposite 40.08 grams is the weigh of 1 mol
The rule of three will be:
40.08 g are contained in 1 mol
1 g may be contained in (1 . 1) / 40.08 = 0.0249 moles
The number of moles contained in 39 L of F2 gas at STP is 1.74mol. Details on how to calculate number of moles can be found below.
<h3>How to calculate number of moles?</h3>
The number of moles of a gas at STP can be calculated using the following formula:
PV = nRT
Where;
- P = pressure
- V = volume
- n = number of moles
- R = gas law constant
- T = temperature
At STP, the following applies:
- T = 273K
- P = 1 atm
- R = 0.0821 Latm/molK
1 × 39 = n × 0.0821 × 273
39 = 22.41n
n = 1.74mol
Therefore, the number of moles contained in 39 L of F2 gas at STP is 1.74mol.
Learn more about number of moles at: brainly.com/question/14919968
Answer:
Th answer is b. convection.
Explanation:
As the heat rises it cools down and it sinks and as the cold sinks it heats up so then it rises back up.
