Answer: An amount of 
heat is required to raise the temperature of 4.64kg of lead from 150°C to 219°C.
Explanation:
Given: mass of lead = 4.64 kg
Convert kg into grams as follows.
The standard value of specific heat of lead is 
.
Formula used to calculate heat is as follows.
where,
q = heat energy
m = mass of substance
C = specific heat of substance
= change in temperature
Substitute the value into above formula as follows.
Thus, we can conclude that heat is required to raise the temperature of 4.64kg of lead from 150°C to 219°C.
Answer:
If the temperature and volume ot a gas increases, the r.m.s. velocity of the molecules in the gas will be 2 times the original r.m.s. molecular velocity.
If T doubles while V is held constant, the new net internal energy of the gas will be 2 times the original internal energy of the gas.
Explanation:
Temperature and root mean square velocity are directly proportional to one anoth. If the temperature increases, root mean square velocity also increases and vice versa, while temperature is also directly proportional to the internal energy of the gas molecules, higher the temperature, higher will be the internal energy and lower the temperature so internal energy will be decreased.
