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kipiarov [429]
3 years ago
14

Which is a reactive metal??

Chemistry
2 answers:
Irina-Kira [14]3 years ago
6 0

The answer would be B.) Sodium, because, "As a part of the alkali metal group in the periodic table, sodium is highly reactive and is never found pure in nature. It tarnishes easily and has a low melting point and density. ... Within the alkali metals, sodium is more reactive than lithium but less reactive than potassium."

(https://chem.libretexts.org/...Metals/Z%3D011_Chemistry_of_Sodium_(Z%3D11))

Dovator [93]3 years ago
5 0

b. sodium is a reactive metal because it has one electron in the outermost electron shell and it gives up one electron to another element.

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What is the pH of a solution with (H3O+)=5.6x10-2M?
balu736 [363]

Answer:

Explanation:

Given parameters:

Concentration of H₃O⁺  = 5.6 x 10⁻²M

Solution:

To solve for the concentration of H₃O⁺ in the solution, we simply use the expression below:

            pH = -log₁₀[H₃O⁺]

where [H₃O⁺] =  5.6 x 10⁻²M is the concentration of H₃O⁺

            pH = -log₁₀[5.6 x 10⁻²] = - x -1.25 = 1.25

3 0
3 years ago
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6)<br> How many moles are in 98.3 grams of aluminum?
8090 [49]

Answer:

1.26

Explanation:

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The _______________________ regulates water quality, air pollution, and solid waste to protect Americans from significant risks
Dmitry_Shevchenko [17]

Answer:

EPA

Explanation:

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6 0
3 years ago
How much energy is released when 33.8 g of water freezes? The heat of fusion for water is 6.02 kJ/mol.
zhuklara [117]

Answer:

11.29Kj

Explanation:

1. find moles of 33.8g of water

Molar mass of H2O: 18.02g/Mol

33.8/18.02= 1.88mols

2. find energy

1.88 x 6.02= 11.29Kj

5 0
3 years ago
The equilibrium constant Kp for the reaction I2(g) + Br2(g) ⇀↽ 2 IBr(g) + 11.7 kJ is 280 at 150◦C. Suppose that a quantity of IB
mixas84 [53]

Answer:

\large \boxed{\text{0.0120 atm }}

Explanation:

The balanced equation is

I₂(g) + Br₂(g) ⇌ 2IBr(g)

Data:

      Kp = 280

p(IBr) = 0.200 atm

1. Set up an ICE table.

Let p = the initial pressure of IBr. Then

\begin{array}{ccccccc}\rm \text{I}_{2}& + & \text{Br}_{2} & \, \rightleftharpoons \, & \text{2IBr} &  &  \\0 & & 0 & & p & & \\+x &   & +x  & & -2x &   &\\x &   & x} &   & 280 & & \\\end{array}

2. Calculate p(I₂)

\begin{array}{rcl}K_{\text{p}}&=&\dfrac{p_{\text{IBr}}^{2}} {p_{\text{I}_2}^{2}}\\\\280&=&{\dfrac{0.200^{2}}{x^{2}}&&\\\\280x^{2} & = &0.0400\\x^{2} & = &\dfrac{0.0400}{280 }\\\\& = & 1.429 \times 10^{-4}\\x & = & \textbf{0.0120 atm}\\\end{array}\\\text{The partial pressure of iodine is $\large \boxed{\textbf{0.0120 atm }}$}}

Check:

\begin{array}{rcl}{\dfrac{0.200^{2}}{0.0120^{2}}}&=&280\\\\280& =& 280\\\end{array}

8 0
3 years ago
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