Answer:
Explanation:
For second order reaction
dC / dt = -k C²
dC /C² = - kdt
Integrating on both sides,
[- 1/C ] = - kt + P , P is a constant .
When t =0 , C = 1.33 M
P = - 1 / 1.33
[- 1/C ] =- - kt - 1 / 1.33
When t = 8.5
[- 1/C ] = - kt - 1 / 1.33
= - 1.18 x 8.5 - 1 / 1.33
= - 10.03 - .7519
= - 10.782
C = .0927 M
= .093 M
Based on experiment 1:
Mass of Hg = 1.00 g
Mass of sulfide = 1.16 g
Mass of sulfur = 1.16 - 1.00 = 0.16 g
# moles of Hg = 1 g/200 gmol-1 = 0.005 moles
# moles of S = 0.16/32 gmol-1 = 0.005 moles
The Hg:S ratio is 1:1, hence the sulfide is HgS
Based on experiment 2:
Mass of Hg taken = 1.56 g
# moles of Hg = 1.56/200 = 0.0078
Mass of S taken = 1.02 g
# moles of S = 1.02/32 = 0.0319
Hence the limiting reagent is Hg
# moles of Hg reacted = # moles of HgS formed = 0.0078 moles
Molar mass of HgS = 232 g/mol
Therefore, mass of HgS formed = 0.0078 * 232 = 1.809 g = 1.81 g
For Single Element Ions (e.g. K+ , Mg2+, P3-) To name positive (+) ions write the name as from the Periodic Table and add the word 'ion' afterwards. To name negative (-) ions write the name from the Periodic Table but replace the ending with 'ide'. Put the word 'ion' after the name.
The right answer is
Table A Organic solvent
No Perfume No Fuel No Anesthetic No Adhesive Yes
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