Answer:
0.20M
Explanation:
Step 1:
Data obtained from the question. This include the following:
Volume of acid, H2SO4 (Va) = 25mL
Molarity of acid, H2SO4 (Ma) =.?
Volume of base, LiOH (Vb) = 83.6mL
Molarity of base, LiOH (Mb) = 0.12 M
Step 2:
The balanced equation for the reaction. This is given below:
H2SO4 + 2LiOH —> Li2SO4 + 2H2O
From the balanced equation above,
Mole ratio of the acid, H2SO4 (nA) = 1
Mole ratio of the base, LiOH (nB)= 2
Step 3:
Determination of the molarity of the acid, H2SO4. This can be obtain as follow:
MaVa/MbVb = nA/nB
Ma x 25 / 0.12 x 83.6 = 1/2
Cross multiply
Ma x 25 x 2 = 0.12 x 83.6
Divide both side by 25 x 2
Ma = (0.12 x 83.6) / (25 x 2)
Ma = 0.20M
Therefore, the molarity of the acid, H2SO4 is 0.20M.
