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3 years ago

I NEED HELP BADLY

Physics

1 answer:

Marrrta [24]3 years ago

7 0

Answer:

a) Andrea's initial momentum, 200 kg m/s

b) Andrea's final momentum, 0

c) Impulse, = - 200 Ns

d) The force that the seat belt exerts on Andrea, - 400 N

Explanation:

Given data,

The initial velocity of the car is, u = 40 m/s

The mass of Andrea, m = 50 kg

The time period of deceleration, a = 0.5 s

The final velocity of the car, v = 0

a) Andrea's initial momentum,

p = mu

= 50 x 40

= 200 kg m/s

b) Andrea's final momentum

P = mv

= 50 x 0

= 0 kg m/s

c) Impulse

I = mv - mu

= 0 - 200

= - 200 Ns

The negative sign indicated that the momentum is decreased.

d) The force that the seat belt exerts on Andrea

F = (mv - mu)t

= (0 - 200) / 0.5

= - 400 Ns

Hence,the force that the seat belt exerts on Andrea is, - 400 N

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Answer:

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3 years ago

A projectile is fired with an initial speed of 100 m/s and angle of elevation 30 degrees. The projectile eventually hits the gro

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Answer:

Explanation:

Given

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Initially vertical velocity is in upward direction but as soon as it reaches the ground its direction change but magnitude remain same.

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3 years ago

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The speed of the second mass after it has moved ℎ=2.47 meters will be 1.09 m/s approximately

<h3>What are we to consider in equilibrium ?</h3>

Whenever the friction in the pulley is negligible, the two blocks will accelerate at the same magnitude. Also, the tension at both sides will be the same.

Given that a large mass m1=5.75 kg and is attached to a smaller mass m2=3.53 kg by a string and the mass of the pulley and string are negligible compared to the other two masses. Mass 1 is started with an initial downward speed of 2.13 m/s.

The acceleration at which they will both move will be;

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Learn more about Equilibrium here: brainly.com/question/517289

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2 years ago

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Answer:

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3 years ago